United States presidential election in New York, 1828

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United States presidential election in New York, 1828
New York
1824 ←
October 31 – December 2, 1828
→ 1832

  Andrew Jackson.jpg JohnQAdams.png
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 20 16
Popular vote 139,412 131,563
Percentage 51.45% 48.55%

The 1828 United States presidential election in New York took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won New York by a margin of 2.9%.

Results[edit]

United States presidential election in New York, 1828[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 139,412 51.45% 20
National Republican John Quincy Adams 131,563 48.55% 16
Totals 270,975 100.0% 36

References[edit]

  1. ^ "1828 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 28 February 2013.