United States presidential election in New York, 1892

From Wikipedia, the free encyclopedia
Jump to: navigation, search
United States presidential election in New York, 1892
New York
1888 ←
November 8, 1892
→ 1896

  Grover Cleveland - NARA - 518139.tif Pach Brothers - Benjamin Harrison.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai E. Stevenson Whitelaw Reid
Electoral vote 36 0
Popular vote 654,868 609,350
Percentage 48.99% 45.58%

New york presidential results 1892.svg

County Results
  Cleveland—60-70%
  Cleveland—50-60%
  Cleveland—<50%
  Harrison—<50%
  Harrison—50-60%
  Harrison—60-70%

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic


The 1892 United States presidential election in New York took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. New York voters chose 36 electors to the Electoral College, which selected the President and Vice President.

New York was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate former Congressman and Assistant Postmaster General Adlai Stevenson I of Illinois. Cleveland and Stevenson defeated the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate U.S. Ambassador to France Whitelaw Reid of Ohio.

Also running a significant campaign that year was the Populist Party candidate, Congressman James B. Weaver of Ohio with his running mate state attorney general James G. Field of Virginia, although Weaver's primarily Western-based campaign did not perform strongly in New York. Despite receiving 8.51% nationally and winning electoral votes from six states, Weaver finished in fifth place in New York State, with only 1.23% of the vote, behind fourth-place Socialist Labor candidate Simon Wing's 1.34%.

Cleveland carried New York State with 48.99% of the vote to Harrison's 45.58%, a victory margin of 3.41%. In a distant third came the Prohibition Party candidate John Bidwell with 2.86%.

New York weighed in for this election as less than 1% more Democratic than the national average.

The Democratic win of New York's electoral votes marked a personal comeback for Grover Cleveland in his home state, as he had narrowly won the state in his initial 1884 presidential campaign, but a narrow defeat here in 1888 had cost him the 1888 election, partially the result of strong opposition to Cleveland from the Tammany Hall machine which dominated New York politics at the time.

Cleveland's relatively narrow statewide victory relied heavily on a strong margin of victory in New York City, receiving more than 60% of the vote in New York County along with victories in Kings County, Queens County, and Richmond County. Cleveland also won nearby Westchester County and Rockland County. Harrison fared better upstate, where he won most counties, although Cleveland carried several upstate counties including Erie County, home to the city of Buffalo, and Albany County, home to the state capital of Albany.

United States presidential election in New York, 1892[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 654,868 48.99% 36
Republican Benjamin Harrison 609,350 45.58% 0
Prohibition John Bidwell 38,190 2.86% 0
Socialist Labor Simon Wing 17,956 1.34% 0
People's James B. Weaver 16,429 1.23% 0
Totals 1,336,793 100.0% 36

See also[edit]

References[edit]

  1. ^ "1892 Presidential Election Results - New York". Dave Leip's U.S. Election Atlas. Retrieved 2013-10-08.