United States presidential election in New York, 1896

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United States presidential election in New York, 1896
New York
1892 ←
November 3, 1896 → 1900

  Mckinley.jpg William Jennings Bryan 2.jpg
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 36 0
Popular vote 819,838 551,369
Percentage 57.58% 38.72%

New york presidential results 1896.svg

County Results
  Bryan—50-60%
  McKinley—50-60%
  McKinley—60-70%
  McKinley—70-80%

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican


The 1896 United States presidential election in New York took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. New York voters chose 36 electors to the Electoral College, which selected the President and Vice President.

New York was won by the Republican nominees, former Governor William McKinley of Ohio and his running mate corporate lawyer Garret Hobart of New Jersey. McKinley and Hobart defeated the Democratic nominees, former Congressman William Jennings Bryan of Nebraska and his running mate industrialist Arthur Sewall of Maine. Bryan also ran and received votes on the Populist Party line, with running mate Congressman Thomas E. Watson of Georgia.

Also in the running was the National Democratic Party (Gold Democrat) candidate, John M. Palmer of Illinois, who ran with former Governor of Kentucky Simon Bolivar Buckner on a platform advocating for the gold standard.

McKinley carried New York State with 57.58% of the vote to Bryan's 38.72%, a victory margin of 18.85%. Palmer came in a distant third with 1.33%.

New York weighed in for this election as about 14% more Republican than the national average.

Bryan, running on a platform of free silver, appealed strongly to Western miners and farmers in the 1896 election, but held little appeal in the Northeastern United States. Consequently he performed especially weakly for a Democrat in New York, losing every county in the state except for Schoharie County upstate. This included a rare Republican victory in New York City, where McKinley outpolled Bryan by about 60,000 votes. McKinley would lose New York City to Bryan in their 1900 re-match four years later, and New York City would not vote Republican again until the Republican landslides of 1920 and 1924, and would subsequently become a reliably Democratic bastion in every election that followed.

United States presidential election in New York, 1896[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 819,838 57.58% 36
Democratic William Jennings Bryan 551,369 38.72% 0
National Democratic John M. Palmer 18,950 1.33% 0
Socialist Labor Charles H. Matchett 17,667 1.24% 0
Prohibition Joshua Levering 16,052 1.13% 0
Totals 1,423,876 100.0% 36

See also[edit]

References[edit]

  1. ^ "1896 Presidential Election Results - New York". Dave Leip's U.S. Election Atlas. Retrieved 2013-10-06.