United States presidential election in New York, 1900

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United States presidential election in New York, 1900
New York
1896 ←
November 6, 1900
→ 1904

  William McKinley by Courtney Art Studio, 1896.jpg William Jennings Bryan 2.jpg
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai E. Stevenson
Electoral vote 36 0
Popular vote 822,013 678,462
Percentage 53.10% 43.83%

New york presidential results 1900.svg

County Results
  Bryan—50-60%
  McKinley—<50%
  McKinley—50-60%
  McKinley—60-70%
  McKinley—70-80%

President before election

William McKinley
Republican

Elected President

William McKinley
Republican


The 1900 United States presidential election in New York took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. New York voters chose 36 electors to the Electoral College, which selected the President and Vice President.

New York was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Governor Theodore Roosevelt of New York. McKinley and Roosevelt defeated the Democratic nominees, former Congressman and 1896 presidential nominee William Jennings Bryan of Nebraska and his running mate former Vice President Adlai Stevenson I of Illinois. Also in the running was the Socialist Party candidate, Eugene V. Debs, who ran with Job Harriman.

McKinley carried New York State with 53.10% of the vote to Bryan's 43.83%, a victory margin of 9.27%.

New York weighed in for this election as about 3% more Republican than the national average.

The 1900 election was a direct re-match between McKinley and Bryan who had run against each other in 1896. While McKinley slightly improved on his national margin, New York swung heavily in Bryan's favor in 1900. In 1896, McKinley had defeated Bryan in the state by 18.85%, sweeping every county in the state except Schoharie County, including rare Republican victories in New York City. McKinley's 1900 margin of victory in New York State was less than half of his 1896 margin, primarily due to dramatic Democratic gains in New York City. While in 1896 Bryan had lost New York City by about 60,000 votes, in 1900 Bryan won a majority of over 30,000 votes in New York City, winning Manhattan, the Bronx, Queens, and Staten Island. New York City would not vote Republican again until the Republican landslides of 1920 and 1924, and would subsequently become a reliably Democratic bastion in every election that followed.


United States presidential election in New York, 1900[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 822,013 53.10% 36
Democratic William Jennings Bryan 678,462 43.83% 0
Prohibition John G. Woolley 22,077 1.43% 0
Socialist Eugene V. Debs 12,869 0.83% 0
Socialist Labor Joseph F. Maloney 12,621 0.82% 0
Totals 1,548,042 100.0% 36

See also[edit]

References[edit]

  1. ^ "1900 Presidential Election Results - New York". Dave Leip's U.S. Election Atlas. Retrieved 2013-10-05.