United States presidential election in New York, 1988
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Main article: United States presidential election, 1988
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| County Results
Dukakis—70-80%
Dukakis—60-70%
Dukakis—50-60%
Dukakis—<50%
Bush—<50%
Bush—50-60%
Bush—60-70%
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The 1988 United States presidential election in New York took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose thirty-six representatives, or electors to the Electoral College, who voted for President and Vice President.
New York was won by Governor Michael Dukakis (D-Massachusetts) with 51.62% of the popular vote over Vice President George H.W. Bush (R-Texas) with 47.52%.[1]
Results [edit]
| United States presidential election in New York, 1988 | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Michael Dukakis | 3,347,882 | 51.62% | 36 | |
| Republican | George H.W. Bush | 3,081,871 | 47.52% | 0 | |
| Right to Life | William Marra | 20,497 | 0.32% | 0 | |
| New Alliance | Lenora Fulani | 15,845 | 0.24% | 0 | |
| Libertarian | Ron Paul | 12,109 | 0.19% | 0 | |
| Workers World | Larry Holmes | 4,179 | 0.06% | 0 | |
| Socialist Workers | James Warren | 3,287 | 0.05% | 0 | |
| Write-in | Edward Winn | 10 | 0.00% | 0 | |
| Write-in | Willa Kenoyer | 3 | 0.00% | 0 | |
| Totals | 6,485,683 | 100.0% | 36 | ||
References [edit]
- ^ "1988 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 13 October 2012.
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