United States presidential election in Ohio, 1828

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United States presidential election in Ohio, 1828
Ohio
1824 ←
October 31 – December 2, 1828
→ 1832

  Andrew Jackson.jpg JohnQAdams.png
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 16 0
Popular vote 67,597 63,396
Percentage 51.60% 48.40%

The 1828 United States presidential election in Ohio took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Ohio by a margin of 3.2%.

Results[edit]

United States presidential election in Ohio, 1828[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 67,597 51.60% 16
National Republican John Quincy Adams 63,396 48.40% 0
Totals 130,993 100.0% 16

References[edit]

  1. ^ "1828 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved 28 February 2013.