United States presidential election in Pennsylvania, 1800

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United States presidential election in Pennsylvania, 1800
1796 ←
1800 → 1804

  Thomas Jefferson by Rembrandt Peale, 1800.jpg US Navy 031029-N-6236G-001 A painting of President John Adams (1735-1826), 2nd president of the United States, by Asher B. Durand (1767-1845)-crop.jpg
Nominee Thomas Jefferson John Adams
Party Democratic-Republican Federalist
Home state Virginia Massachusetts
Running mate Aaron Burr Charles Cotesworth Pinckney
Electoral vote 8 7
Percentage 64.52% 35.48%

The 1800 United States presidential election in Pennsylvania took place as part of the 1800 United States presidential election. The Pennsylvania General Assembly, consisting of the State Senate and State House chose 15 representatives, or electors to the Electoral College,[1] who voted for President and Vice President. The 1800 election marks the only time in Pennsylvania history that presidential electors were chosen by the State Legislature.[2]

Pennsylvania elected eight electors supportive the Democratic-Republican candidate, Thomas Jefferson and seven electors supportive of the Federalist candidate, John Adams.


United States presidential election in Pennsylvania, 1800[2]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Thomas Jefferson 60 64.52% 8
Federalist John Adams 33 35.48% 7
N/A Not voting 7 - -
N/A Not sworn in 2 - -
Totals 93 100.0% 15

Note: These are the vote totals for each candidate for the entire State Assembly, including the State Senate and the State House.


  1. ^ "1800 ELECTION FOR THE FOURTH TERM, 1801-1805". National Archives. Retrieved 4 August 2012. 
  2. ^ a b "Pennsylvania Presidential Election Returns 1800". Wilkes University. Retrieved 4 August 2012.