United States presidential election in Pennsylvania, 1864

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United States presidential election in Pennsylvania, 1864
Pennsylvania
1860 ←
November 8, 1864
→ 1868

  Abraham Lincoln November 1863.jpg GeorgeMcClellan.png
Nominee Abraham Lincoln George B. McClellan
Party National Union Party Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 26 0
Popular vote 296,391 276,316
Percentage 51.75% 48.25%

The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won Pennsylvania by a margin of 3.5%.

Results[edit]

United States presidential election in Pennsylvania, 1864[1]
Party Candidate Votes Percentage Electoral votes
National Union Abraham Lincoln 296,391 51.75% 26
Democratic George B. McClellan 276,316 48.25% 0
Totals 572,707 100.0% 26

References[edit]

  1. ^ "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 3 August 2012.