United States presidential election in Pennsylvania, 1896

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United States presidential election in Pennsylvania, 1896
Pennsylvania
1892 ←
November 3, 1896
→ 1900

  William McKinley by Courtney Art Studio, 1896.jpg WilliamJBryan1902.png
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 32 0
Popular vote 728,300 433,228
Percentage 60.98% 36.27%

Pennsylvania Presidential Election Results by County, 1896.svg

County results

The 1896 United States presidential election in Pennsylvania took place on November 3, 1896 throughout 45 states. Voters chose 32 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania overwhelmingly voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won Pennsylvania by a landslide margin of 24.71%.


Results[edit]

United States presidential [1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 728,300 60.98% 32
Democratic William Jennings Bryan 433,228 36.27% 0
Prohibition Joshua Levering 19,274 1.61% 0
National Democratic John Palmer 11,000 0.92% 0
Socialist Labor Charles Matchett 1,683 0.14% 0
National Party Charles Bentley 870 0.07% 0

References[edit]