United States presidential election in Pennsylvania, 1988

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United States presidential election in Pennsylvania, 1988
Pennsylvania
1984 ←
November 8, 1988
→ 1992

  43 George H.W. Bush 3x4.jpg Dukakis1988rally cropped.jpg
Nominee George H.W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 25 0
Popular vote 2,300,087 2,194,944
Percentage 50.70% 48.39%

Pennsylvania Presidential Election Results by County, 1988.svg

County results

The 1988 United States presidential election in Pennsylvania took place on November 8, 1988 throughout all 50 states and D.C., which was part of the 1988 United States presidential election. Voters chose 25 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania narrowly voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts governor Michael Dukakis. As of 2012, this is the last election where Pennsylvania was carried by the Republican presidential candidate. This was also the first election since 1932 that Pennsylvania did not vote the same as neighboring New York, and the last time as of 2012 that has happened.


Results[edit]

United States presidential[1]
Party Candidate Votes Percentage Electoral votes
Republican George H. W. Bush 2,300,087 50.70% 25
Democratic Michael Dukakis 2,194,944 48.39% 0
Consumer Eugene McCarthy 19,158 0.42% 0
Libertarian Ron Paul 12,051 0.27% 0
New Alliance Lenora Fulani 4,379 0.10% 0
America First David Duke 3,444 0.08% 0
Workers' League Edward Winn 2,188 0.05% 0

References[edit]

See also[edit]