United States presidential election in Vermont, 1832

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United States presidential election in Vermont, 1832
Vermont
1828 ←
November 2 – December 5, 1832
→ 1836

  WilliamWirt.png Henry Clay.JPG Andrew Jackson.jpg
Nominee William Wirt Henry Clay Andrew Jackson
Party Anti-Masonic National Republican Democratic
Home state Maryland Kentucky Tennessee
Running mate Amos Ellmaker John Sergeant Martin Van Buren
Electoral vote 7 0 0
Popular vote 13,106 11,152 7,870
Percentage 40.79% 34.71% 24.50%

The 1832 United States presidential election in Vermont took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Anti-Masonic Party candidate, William Wirt, over the National Republican candidate, Henry Clay, and the Democratic Party candidate, Andrew Jackson. Wirt won Vermont, the only state he carried in 1832, by a margin of 6.08%.

Results[edit]

United States presidential election in Vermont, 1832[1]
Party Candidate Votes Percentage Electoral votes
Anti-Masonic William Wirt 13,106 40.79% 7
National Republican Henry Clay 11,152 34.71% 0
Democratic Andrew Jackson 7,870 24.50% 0
Totals 32,128 100.0% 7

References[edit]

  1. ^ "1832 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 12 April 2013.