1844 United States presidential election in Vermont

Main article: 1844 United States presidential election

1844 United States presidential election in Vermont

November 1 - December 4, 1844

Nominee Henry Clay James K. Polk James G. Birney Party Whig Democratic Liberty Home state Kentucky Tennessee Michigan Running mate Theodore Frelinghuysen George M. Dallas Thomas Morris Electoral vote 6 0 0 Popular vote 26,780 18,049 3,970 Percentage 54.84% 36.96% 8.13%

County Results Clay   40-50%   50-60%   60-70% Polk   40-50%   50-60%

President before election John Tyler Independent Elected President James K. Polk Democratic

The 1844 United States presidential election in Vermont took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk and Liberty candidate James G. Birney. Clay won Vermont by a margin of 17.88%.

With 54.84% of the popular vote, Vermont would prove to be Henry Clay's second strongest state after Rhode Island. Vermont would also prove to be James G. Birney's third strongest state after New Hampshire and Massachusetts.

Results

1844 United States presidential election in Vermont
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	26,780	54.84%	6	100.00%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	18,049	36.96%	0	0.00%
	Liberty	James G. Birney of Michigan	Thomas Morris of Ohio	3,970	8.13%	0	0.00%
	N/A	Others	Others	30	0.06%	0	0.00%
Total				48,829	100.00%	6	100.00%

See also

• United States presidential elections in Vermont