United States presidential election in Vermont, 1860

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United States presidential election in Vermont, 1860
Vermont
1856 ←
November 2, 1860 → 1864

  Abraham Lincoln by Alexander Helser, 1860-crop.jpg StephenADouglas.png
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel Vespasian Johnson
Electoral vote 5 0
Popular vote 33,808 8,649
Percentage 75.7% 19.4%

President before election

Franklin Pierce
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Vermont took place on November 2, 1860 throughout all 33 states which was part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for President and Vice President.

Vermont was the birth state of U.S. presidential candidate Stephen A. Douglas.

Republican candidate Abraham Lincoln won by about 50 percentage points.

Results[edit]

Presidential Candidate Party Electoral Vote (EV) Popular Vote Percentage
Abraham Lincoln Republican 5 33,808 75.7%
Stephen A. Douglas Northern Democratic 0 8,649 19.4%
John Bell Constitutional Union 0 1,969 4.4%
John C. Breckinridge Southern Democratic 0 218 0.5%