United States presidential election in Vermont, 1916

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United States presidential election in Vermont, 1916
Vermont
1912 ←
November 7, 1916 → 1920

  Governor Charles Evans Hughes.jpg Woodrow Wilson-H&E.jpg
Nominee Charles E. Hughes Woodrow Wilson
Party Republican Democratic
Home state New York New Jersey
Running mate Charles W. Fairbanks Thomas R. Marshall
Electoral vote 4 0
Popular vote 40,250 22,708
Percentage 62.43% 35.22%

Vermont Election Results by County 1916.svg

County Results
  Wilson—50-60%
  Hughes—50-60%
  Hughes—60-70%
  Hughes—70-80%

President before election

Woodrow Wilson
Democratic

Elected President

Woodrow Wilson
Democratic

The 1916 United States Presidential Election in Vermont took place on November 7, 1916 as part of the 1916 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont was won by the Republican nominee, U.S. Supreme Court Justice Charles Evans Hughes of New York, and his running mate Senator Charles W. Fairbanks of Indiana. Hughes and Fairbanks defeated the Democratic nominees, incumbent Democratic President Woodrow Wilson and Vice President Thomas R. Marshall.

Hughes won a decisive victory with 62.43% of the vote, to Wilson's 35.22%, a Republican victory margin of 27.21%.

Vermont historically was a bastion of liberal Northeastern Republicanism, and by 1916 the Green Mountain State had gone Republican in every presidential election since the founding of the Republican Party. From 1856 to 1912, Vermont had had the longest streak of voting Republican of any state, having never voted Democratic before, and this tradition continued in 1916.

In 1912, Vermont had been one of only two states (along with Utah) to vote for incumbent Republican President William Howard Taft, who was pushed into 3rd place nationally by the strong third party candidacy of Theodore Roosevelt, a former Republican president who had run in 1912 with his own Bull Moose Party. Taft and Roosevelt had split the Republican vote nationally in 1912, and in Vermont, Taft edged out Roosevelt 37-35, while Wilson had received only 24% of the vote. With the Republican base re-united behind Charles Evans Hughes in 1916, the GOP scored a landslide win in Vermont with over 62% of the vote, although Wilson also gained 11 points in support from his 1912 showing.

Hughes carried 13 of the state's 14 counties, breaking 60% of the vote in 8 of them, and even breaking 70% in 2 counties. Wilson's only county victory came from sparsely populated Grand Isle County in the far northwest of the state, which had also been the only county in the state to give Wilson a plurality win in 1912.

As Wilson narrowly won re-election nationally, Vermont weighed in as over 30% more Republican than the national average in the 1916 election, making it the most Republican state in the union.


Results[edit]

United States presidential election in Vermont, 1916[1]
Party Candidate Votes Percentage Electoral votes
Republican Charles Evans Hughes 40,250 62.43% 4
Democratic Woodrow Wilson 22,708 35.22% 0
Socialist Allan L. Benson 798 1.24% 0
Prohibition Frank Hanly 709 1.10% 0
N/A Write-ins 10 0.02% 0
Totals 64,475 100.00% 4


References[edit]

  1. ^ "1916 Presidential General Election Results - Vermont". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 2013-08-02.