United States presidential election in Vermont, 1948

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United States presidential election in Vermont, 1948
Vermont
1944 ←
November 2, 1948
→ 1952

  ThomasDewey.png Harry S. Truman.jpg
Nominee Thomas E. Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 3 0
Popular vote 75,926 45,557
Percentage 61.54% 36.92%

Vermont Election Results by County 1948.svg

County Results
  Truman—50-60%
  Dewey—50-60%
  Dewey—60-70%
  Dewey—70-80%

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States Presidential Election in Vermont took place on November 2, 1948 as part of the 1948 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Republican nominee, former Governor Thomas E. Dewey of New York, over the Democratic nominee, incumbent President Harry S. Truman of Missouri. Dewey's running mate was Governor Earl Warren of California, while Truman ran with Senator Alben W. Barkley of Kentucky.

Dewey took a landslide 61.54% of the vote to Truman's 36.92%, a victory margin of 24.61%. Progressive Party candidate Henry A. Wallace came in a distant third with 1.04%.

Vermont historically was a bastion of liberal Northeastern Republicanism, and by 1948 the Green Mountain State had gone Republican in every presidential election since the founding of the Republican Party. From 1856 to 1944, Vermont had had the longest streak of voting Republican of any state, having never voted Democratic before, and this tradition easily continued in 1948 with Dewey's decisive win.

Vermont had been one of only two states (along with Maine) to reject Democrat Franklin D. Roosevelt in all four of his presidential campaigns, even in the nationwide Democratic landslides of 1932 and 1936. But FDR had improved dramatically on previous Democrats' performances in Vermont, and in an opposite trend of the nation, had actually been more Democratic in the 1940s than in either of the 1930s landslides, with Roosevelt coming within 10 points of winning Vermont in 1940. Thus Dewey's decisive win with 61.54% marked the first time since 1928 that a Republican would break 60% of the vote in Vermont.

Dewey carried 11 of the state's 14 counties, breaking 60% in 9 of them, and in 5 of those even broke 70%. But the three northwestern counties of Vermont had been Democratic enclaves in an otherwise Republican state throughout the 1930s and 1940s, and Truman once again won Chittenden County, Franklin County and Grand Isle County for the Democrats. Dewey did manage to win back sparsely populated Essex County, in the northeast of the state, which had defected to the Democrats and voted for Roosevelt in 1940 and 1944.

Results[edit]

United States presidential election in Vermont, 1948[1]
Party Candidate Votes Percentage Electoral votes
Republican Thomas E. Dewey 75,926 61.54% 3
Democratic Harry S. Truman 45,557 36.92% 0
Progressive Henry A. Wallace 1,279 1.04% 0
Socialist Norman Thomas 585 0.47% 0
N/A Write-ins 35 0.03% 0
Totals 123,382 100.00% 3


References[edit]

  1. ^ "1948 Presidential General Election Results - Vermont". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 2013-08-02.