Yankeetown, Indiana
From Wikipedia, the free encyclopedia
| Yankeetown | |
|---|---|
| — Town — | |
 Yankeetown
|
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| Coordinates: 37°55′03″N 87°17′52″W / 37.9175°N 87.29778°WCoordinates: 37°55′03″N 87°17′52″W / 37.9175°N 87.29778°W | |
| Country | United States |
| State | Indiana |
| County | Warrick |
| Township | Anderson |
| Elevation[1] | 449 ft (137 m) |
| ZIP code | 47630 |
| FIPS code | 18-85760[2] |
| GNIS feature ID | 446363 |
Yankeetown is an unincorporated town in Anderson Township, Warrick County, Indiana.
[edit] Geography
Yankeetown is located at 37°55′03″N 87°17′52″W / 37.9175°N 87.29778°W.
[edit] References
- ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. http://geonames.usgs.gov. Retrieved 2008-01-31.
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
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