Talk:Damping: Difference between revisions

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I agree

I think it should be merged there is no reason to separate a constant from its concept. —Preceding unsigned comment added by 71.127.184.53 (talk) 17:57, 3 October 2007 (UTC)[reply]

is this right?

zeta=h/2/sqrt(h*k) ??
Angular velocity is w^2=k/m
and damping coefficient is h=2*zeta*w
or
zeta=h/2/w
or
zeta=h/2/sqrt(k/m)

They cant both be right
zeta=h/2/sqrt(k/m) vs. zeta=h/2/sqrt(h*k)

Regarding the claim that bells ring with an almost pure sinusoidal tone

I think the argument for this is very unclear. In my experience, and as far as I know, bells are not constructed to make pure tones. On the contrary, they make a very dissonant noise.

I suppose the article's claim can be translated to that a high quality bell can be viewed as an underdamped, linear time-invariant system, and that it thus, after an initial impulse, will follow the curve of a decaying exponential (zero) plus an exponentially decaying sinusoid. I do not believe the premise is correct, and thus the conclusion is not obvious to me.

"High quality bells" are not mentioned in the article about the pure tone.

@@ Line 18: / Line 18: @@
 They cant both be right<br />
 zeta=h/2/sqrt(k/m) vs. zeta=h/2/sqrt(h*k) <br />
+== Regarding the claim that bells ring with an almost pure sinusoidal tone ==
+I think the argument for this is very unclear. In my experience, and as far as I know, bells are not constructed to make pure tones. On the contrary, they make a very dissonant noise.
+I suppose the article's claim can be translated to that a high quality bell can be viewed as an underdamped, linear time-invariant system, and that it thus, after an initial impulse, will follow the curve of a decaying exponential (zero) plus an exponentially decaying sinusoid. I do not believe the premise is correct, and thus the conclusion is not obvious to me.
+"High quality bells" are not mentioned in the article about the pure tone.