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Classes (I) Published by Juan Soulie Last update on May 7, 2007 at 9:30am
A class is an expanded concept of a data structure: instead of holding only data, it can hold both data and functions. An object is an instantiation of a class. In terms of variables, a class would be the type, and an object would be the variable.
Classes are generally declared using the keyword class, with the following format:
class class_name {
access_specifier_1: member1; access_specifier_2: member2; ... } object_names;
Where class_name is a valid identifier for the class, object_names is an optional list of names for objects of this class. The body of the declaration can contain members, that can be either data or function declarations, and optionally access specifiers.
All is very similar to the declaration on data structures, except that we can now include also functions and members, but also this new thing called access specifier. An access specifier is one of the following three keywords: private, public or protected. These specifiers modify the access rights that the members following them acquire:
private members of a class are accessible only from within other members of the same class or from their friends.
protected members are accessible from members of their same class and from their friends, but also from members of their derived classes.
Finally, public members are accessible from anywhere where the object is visible.
By default, all members of a class declared with the class keyword have private access for all its members. Therefore, any member that is declared before one other class specifier automatically has private access. For example:
class CRectangle {
int x, y; public: void set_values (int,int); int area (void); } rect;
Declares a class (i.e., a type) called CRectangle and an object (i.e., a variable) of this class called rect. This class contains four members: two data members of type int (member x and member y) with private access (because private is the default access level) and two member functions with public access: set_values() and area(), of which for now we have only included their declaration, not their definition.
Notice the difference between the class name and the object name: In the previous example, CRectangle was the class name (i.e., the type), whereas rect was an object of type CRectangle. It is the same relationship int and a have in the following declaration:
int a;
where int is the type name (the class) and a is the variable name (the object).
After the previous declarations of CRectangle and rect, we can refer within the body of the program to any of the public members of the object rect as if they were normal functions or normal variables, just by putting the object's name followed by a dot (.) and then the name of the member. All very similar to what we did with plain data structures before. For example:
rect.set_values (3,4); myarea = rect.area();
The only members of rect that we cannot access from the body of our program outside the class are x and y, since they have private access and they can only be referred from within other members of that same class.
Here is the complete example of class CRectangle:
// classes example
- include <iostream>
using namespace std;
class CRectangle {
int x, y; public: void set_values (int,int); int area () {return (x*y);}
};
void CRectangle::set_values (int a, int b) {
x = a; y = b;
}
int main () {
CRectangle rect; rect.set_values (3,4); cout << "area: " << rect.area(); return 0;
}
area: 12
The most important new thing in this code is the operator of scope (::, two colons) included in the definition of set_values(). It is used to define a member of a class from outside the class declaration itself.
You may notice that the definition of the member function area() has been included directly within the definition of the CRectangle class given its extreme simplicity, whereas set_values() has only its prototype declared within the class, but its definition is outside it. In this outside declaration, we must use the operator of scope (::) to specify that we are defining a function that is a member of the class CRectangle and not a regular global function.
The scope operator (::) specifies the class to which the member being declared belongs, granting exactly the same scope properties as if this function definition was directly included within the class definition. For example, in the function set_values() of the previous code, we have been able to use the variables x and y, which are private members of class CRectangle, which means they are only accessible from other members of their class.
The only difference between defining a class member function completely within its class and to include only the prototype and later its definition, is that in the first case the function will automatically be considered an inline member function by the compiler, while in the second it will be a normal (not-inline) class member function, which in fact supposes no difference in behavior.
Members x and y have private access (remember that if nothing else is said, all members of a class defined with keyword class have private access). By declaring them private we deny access to them from anywhere outside the class. This makes sense, since we have already defined a member function to set values for those members within the object: the member function set_values(). Therefore, the rest of the program does not need to have direct access to them. Perhaps in a so simple example as this, it is difficult to see an utility in protecting those two variables, but in greater projects it may be very important that values cannot be modified in an unexpected way (unexpected from the point of view of the object).
One of the greater advantages of a class is that, as any other type, we can declare several objects of it. For example, following with the previous example of class CRectangle, we could have declared the object rectb in addition to the object rect:
// example: one class, two objects
- include <iostream>
using namespace std;
class CRectangle {
int x, y; public: void set_values (int,int); int area () {return (x*y);}
};
void CRectangle::set_values (int a, int b) {
x = a; y = b;
}
int main () {
CRectangle rect, rectb; rect.set_values (3,4); rectb.set_values (5,6); cout << "rect area: " << rect.area() << endl; cout << "rectb area: " << rectb.area() << endl; return 0;
}
rect area: 12
rectb area: 30
In this concrete case, the class (type of the objects) to which we are talking about is CRectangle, of which there are two instances or objects: rect and rectb. Each one of them has its own member variables and member functions.
Notice that the call to rect.area() does not give the same result as the call to rectb.area(). This is because each object of class CRectangle has its own variables x and y, as they, in some way, have also their own function members set_value() and area() that each uses its object's own variables to operate.
That is the basic concept of object-oriented programming: Data and functions are both members of the object. We no longer use sets of global variables that we pass from one function to another as parameters, but instead we handle objects that have their own data and functions embedded as members. Notice that we have not had to give any parameters in any of the calls to rect.area or rectb.area. Those member functions directly used the data members of their respective objects rect and rectb.
Constructors and destructors
Objects generally need to initialize variables or assign dynamic memory during their process of creation to become operative and to avoid returning unexpected values during their execution. For example, what would happen if in the previous example we called the member function area() before having called function set_values()? Probably we would have gotten an undetermined result since the members x and y would have never been assigned a value.
In order to avoid that, a class can include a special function called constructor, which is automatically called whenever a new object of this class is created. This constructor function must have the same name as the class, and cannot have any return type; not even void.
We are going to implement CRectangle including a constructor:
// example: class constructor
- include <iostream>
using namespace std;
class CRectangle {
int width, height; public: CRectangle (int,int); int area () {return (width*height);}
};
CRectangle::CRectangle (int a, int b) {
width = a; height = b;
}
int main () {
CRectangle rect (3,4); CRectangle rectb (5,6); cout << "rect area: " << rect.area() << endl; cout << "rectb area: " << rectb.area() << endl; return 0;
}
rect area: 12
rectb area: 30
As you can see, the result of this example is identical to the previous one. But now we have removed the member function set_values(), and have included instead a constructor that performs a similar action: it initializes the values of x and y with the parameters that are passed to it.
Notice how these arguments are passed to the constructor at the moment at which the objects of this class are created:
CRectangle rect (3,4); CRectangle rectb (5,6);
Constructors cannot be called explicitly as if they were regular member functions. They are only executed when a new object of that class is created.
You can also see how neither the constructor prototype declaration (within the class) nor the latter constructor definition include a return value; not even void.
The destructor fulfills the opposite functionality. It is automatically called when an object is destroyed, either because its scope of existence has finished (for example, if it was defined as a local object within a function and the function ends) or because it is an object dynamically assigned and it is released using the operator delete.
The destructor must have the same name as the class, but preceded with a tilde sign (~) and it must also return no value.
The use of destructors is especially suitable when an object assigns dynamic memory during its lifetime and at the moment of being destroyed we want to release the memory that the object was allocated.
// example on constructors and destructors
- include <iostream>
using namespace std;
class CRectangle {
int *width, *height; public: CRectangle (int,int); ~CRectangle (); int area () {return (*width * *height);}
};
CRectangle::CRectangle (int a, int b) {
width = new int; height = new int; *width = a; *height = b;
}
CRectangle::~CRectangle () {
delete width; delete height;
}
int main () {
CRectangle rect (3,4), rectb (5,6); cout << "rect area: " << rect.area() << endl; cout << "rectb area: " << rectb.area() << endl; return 0;
}
rect area: 12
rectb area: 30
Overloading Constructors
Like any other function, a constructor can also be overloaded with more than one function that have the same name but different types or number of parameters. Remember that for overloaded functions the compiler will call the one whose parameters match the arguments used in the function call. In the case of constructors, which are automatically called when an object is created, the one executed is the one that matches the arguments passed on the object declaration:
// overloading class constructors
- include <iostream>
using namespace std;
class CRectangle {
int width, height; public: CRectangle (); CRectangle (int,int); int area (void) {return (width*height);}
};
CRectangle::CRectangle () {
width = 5; height = 5;
}
CRectangle::CRectangle (int a, int b) {
width = a; height = b;
}
int main () {
CRectangle rect (3,4); CRectangle rectb; cout << "rect area: " << rect.area() << endl; cout << "rectb area: " << rectb.area() << endl; return 0;
}
rect area: 12
rectb area: 25
In this case, rectb was declared without any arguments, so it has been initialized with the constructor that has no parameters, which initializes both width and height with a value of 5.
Important: Notice how if we declare a new object and we want to use its default constructor (the one without parameters), we do not include parentheses ():
CRectangle rectb; // right CRectangle rectb(); // wrong!
Default constructor
If you do not declare any constructors in a class definition, the compiler assumes the class to have a default constructor with no arguments. Therefore, after declaring a class like this one:
class CExample {
public: int a,b,c; void multiply (int n, int m) { a=n; b=m; c=a*b; }; };
The compiler assumes that CExample has a default constructor, so you can declare objects of this class by simply declaring them without any arguments:
CExample ex;
But as soon as you declare your own constructor for a class, the compiler no longer provides an implicit default constructor. So you have to declare all objects of that class according to the constructor prototypes you defined for the class:
class CExample {
public: int a,b,c; CExample (int n, int m) { a=n; b=m; }; void multiply () { c=a*b; }; };
Here we have declared a constructor that takes two parameters of type int. Therefore the following object declaration would be correct:
CExample ex (2,3);
But, CExample ex;
Would not be correct, since we have declared the class to have an explicit constructor, thus replacing the default constructor.
But the compiler not only creates a default constructor for you if you do not specify your own. It provides three special member functions in total that are implicitly declared if you do not declare your own. These are the copy constructor, the copy assignment operator, and the default destructor.
The copy constructor and the copy assignment operator copy all the data contained in another object to the data members of the current object. For CExample, the copy constructor implicitly declared by the compiler would be something similar to:
CExample::CExample (const CExample& rv) {
a=rv.a; b=rv.b; c=rv.c; }
Therefore, the two following object declarations would be correct:
CExample ex (2,3); CExample ex2 (ex); // copy constructor (data copied from ex)
Pointers to classes
It is perfectly valid to create pointers that point to classes. We simply have to consider that once declared, a class becomes a valid type, so we can use the class name as the type for the pointer. For example:
CRectangle * prect;
is a pointer to an object of class CRectangle.
As it happened with data structures, in order to refer directly to a member of an object pointed by a pointer we can use the arrow operator (->) of indirection. Here is an example with some possible combinations:
// pointer to classes example
- include <iostream>
using namespace std;
class CRectangle {
int width, height; public: void set_values (int, int); int area (void) {return (width * height);}
};
void CRectangle::set_values (int a, int b) {
width = a; height = b;
}
int main () {
CRectangle a, *b, *c; CRectangle * d = new CRectangle[2]; b= new CRectangle; c= &a; a.set_values (1,2); b->set_values (3,4); d->set_values (5,6); d[1].set_values (7,8); cout << "a area: " << a.area() << endl; cout << "*b area: " << b->area() << endl; cout << "*c area: " << c->area() << endl; cout << "d[0] area: " << d[0].area() << endl; cout << "d[1] area: " << d[1].area() << endl; delete[] d; delete b; return 0;
}
a area: 2
- b area: 12
- c area: 2
d[0] area: 30 d[1] area: 56
Next you have a summary on how can you read some pointer and class operators (*, &, ., ->, [ ]) that appear in the previous example:
expression can be read as
- x pointed by x
&x address of x x.y member y of object x x->y member y of object pointed by x (*x).y member y of object pointed by x (equivalent to the previous one) x[0] first object pointed by x x[1] second object pointed by x x[n] (n+1)th object pointed by x
Be sure that you understand the logic under all of these expressions before proceeding with the next sections. If you have doubts, read again this section and/or consult the previous sections about pointers and data structures.
Classes defined with struct and union
Classes can be defined not only with keyword class, but also with keywords struct and union.
The concepts of class and data structure are so similar that both keywords have in C++ the exact same functionality except that the members of classes declared with keyword struct have public access by default, instead of private access, as classes declared with keyword class have. That is the only difference. For all other purposes both keywords are equivalent.
The concept under unions is different from than of struct and class, since unions only store one data member at a time, but they are also classes and thus can also hold function members. The default access in union classes is public.