1822 Maryland gubernatorial election
Appearance
December 9, 1822
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The 1822 Maryland gubernatorial election was held on December 9, 1822, in order to elect the Governor of Maryland. Democratic-Republican nominee and former member of the Maryland House of Delegates Samuel Stevens Jr. was elected by the Maryland General Assembly against Federalist nominee James B. Robins.[1]
General election
[edit]On election day, December 9, 1822, Democratic-Republican nominee Samuel Stevens Jr. was elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Stevens was sworn in as the 18th Governor of Maryland on December 16, 1822.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Samuel Stevens Jr. | 63 | 79.75 | |
| Federalist | James B. Robins | 16 | 20.25 | |
| Total votes | 79 | 100.00 | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Samuel Stevens Jr". National Governors Association. Retrieved 2024-04-27.
- ^ "MD Governor". ourcampaigns.com. August 25, 2004. Retrieved 2024-04-27.