1828 United States presidential election in Pennsylvania

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1828 United States presidential election in Pennsylvania

← 1824 October 31 – December 2, 1828 1832 →
  Andrew Jackson.jpg JohnQAdams.jpg
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 28 0
Popular vote 101,652 50,848
Percentage 66.66% 33.34%

President before election

John Quincy Adams

Elected President

Andrew Jackson

The 1828 United States presidential election in Pennsylvania took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Pennsylvania by a margin of 33.32%.


United States presidential election in Pennsylvania, 1828[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 101,652 66.66% 28
National Republican John Quincy Adams 50,848 33.34% 0
Totals 152,500 100.0% 28


  1. ^ "1828 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 4 August 2012.