1836 United States presidential election in Georgia

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United States presidential election in Georgia, 1836
Flag of the State of Georgia (non-official).svg
← 1832 November 3 – December 7, 1836 1840 →
  HLWhite.jpg Van Buren.jpg
Nominee Hugh White Martin Van Buren
Party Whig Democratic
Home state Tennessee New York
Running mate John Tyler Richard Johnson
Electoral vote 11 0
Popular vote 24,481 22,778
Percentage 51.80% 48.20%

The 1836 United States presidential election in Georgia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Georgia voted for Whig candidate Hugh White over the Democratic candidate, Martin Van Buren. White won Georgia by a margin of 3.6%.

Results[edit]

United States presidential election in Georgia, 1836[1]
Party Candidate Votes Percentage Electoral votes
Whig Hugh White 24,481 51.80% 11
Democratic Martin Van Buren 22,778 48.20% 0
Totals 47,259 100.0% 11

References[edit]

  1. ^ "1836 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 4 August 2012.