1836 United States presidential election in New York
|Elections in New York State|
The 1836 United States presidential election in New York took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose forty-two representatives, or electors to the Electoral College, who voted for President and Vice President.
|United States presidential election in New York, 1836|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Democratic||Martin Van Buren of New York||Richard M. Johnson of Kentucky||166,795||54.63%||42||100.00%|
|Whig||William Henry Harrison of Ohio||Francis Granger of New York||138,548||45.37%||0||0.00%|
- "1836 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 23 December 2013.
|This New York elections-related article is a stub. You can help Wikipedia by expanding it.|