1841 Chicago mayoral election

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Chicago mayoral election, 1841
← 1840 March 5, 1841 1842 →
  Francis-sherman (1).jpg 3x4.svg
Candidate Francis Cornwall Sherman Isaac R. Gavin
Party Democratic Whig
Popular vote 460 419
Percentage 52.33% 47.67%

Mayor before election

Alexander Loyd
Democratic

Elected Mayor

Francis Cornwall Sherman
Democratic

The 1840 Chicago mayoral election saw Democrat Francis Cornwall Sherman defeat Whig Isaac R. Gavin by a 4.7% margin of victory.

The election was held on March 5.[1]

Sherman was the proprietor of the Sherman House Hotel[2]

Prior elections had been conducted in a manner requiring voters to state their party preference upon entering their polling place. This election was conducted in a manner which provided voters more privacy/anonymity than the previous four mayoral elections had.[3]

Results[edit]

1841 Chicago mayoral election[4]
Party Candidate Votes %
Democratic Francis Cornwall Sherman 460 52.33
Whig Isaac R. Gavin 419 47.67
Turnout 879

References[edit]

  1. ^ "Mayor Francis Cornwall Sherman Biography". Chicago Public Library. Retrieved 23 December 2018.
  2. ^ "Political History of Chicago: (covering the Period from 1837 to 1887) Local Politics from the City's Birth; Chicago's Mayors, Aldermen and Other Officials; County and Federal Officers; the Fire and Police Departments; the Haymarket Horror; Miscellaneous" by M. L. Ahern (January 1, 1886)
  3. ^ 10 things you might not know about Chicago mayoral elections Mark Jacob and Stephan Benzkofer March 10, 2015
  4. ^ "RaceID=486020". Our Campaigns. Retrieved December 23, 2018.