1852 United States presidential election in Illinois

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1852 United States presidential election in Illinois

← 1848 November 2, 1852 1856 →
  Mathew Brady - Franklin Pierce crop.jpg Winfield Scott by Fredricks, 1862 crop.jpg JP-Hale crop.jpg
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George W. Julian
Electoral vote 11 0 0
Popular vote 80,378 64,733 9,863
Percentage 51.87% 41.77% 6.36%

President before election

Millard Fillmore

Elected President

Franklin Pierce

The 1852 United States presidential election in Illinois took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.

Illinois voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott and Free Soil candidate John P. Hale. Pierce won Illinois by a margin of 10.10%.


1852 United States presidential election in Illinois[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 80,378 51.87% 11 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 64,733 41.77% 0 0.00%
Free Soil John P. Hale of New Hampshire George W. Julian of Indiana 9,863 6.36% 0 0.00%
Total 154,974 100.00% 11 100.00%


  1. ^ "1852 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved 2 December 2017.
  2. ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.