1856 United States presidential election in Georgia

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United States presidential election in Georgia, 1856

← 1852 November 4, 1856 1860 →
  Hon. James Buchanan - NARA - 528318-crop.jpg Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic American
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote 10 0
Popular vote 56,581 42,439
Percentage 57.14% 42.86%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Georgia took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for president and vice president.

Georgia voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Georgia by a margin of 14.28%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results[edit]

United States presidential election in Georgia, 1856[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 56,581 57.14% 10 100.00%
American Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 42,439 42.86% 0 0.00%
Total 99,020 100.00% 10 100.00%

References[edit]

  1. ^ "1856 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 3 December 2017.
  2. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.