1880 United States presidential election in Florida

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United States presidential election in Florida, 1880

← 1876 November 2, 1880 1884 →
Turnout19.15% of the total population Decrease 5.77 pp[1]
  WinfieldScottHancock.png JamesGarfield.png
Nominee Winfield Scott Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William Hayden English Chester A. Arthur
Electoral vote 4 0
Popular vote 27,964 23,654
Percentage 54.17% 41.05%

President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

The 1880 United States presidential election in Florida took place on November 2, 1880, as part of the 1880 United States presidential election. Florida voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

Florida was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 54.17% of the popular vote, against Representative James Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 41.05% of the vote.[2]

Results[edit]

United States presidential election in North Carolina, 1868[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 27,964 54.17% 4 100.00%
Republican James Garfield of Ohio Chester A. Arthur of New York 23,654 45.83% 0 0.00%
Total 51,618 100.00% 4 100.00%

References[edit]

  1. ^ "1884 Presidential Election Results Florida Total Population Turnout".
  2. ^ a b c "1880 Presidential Election Results Florida".