1880 United States presidential election in Nevada

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United States presidential election in Nevada, 1880

← 1876 November 2, 1880 1884 →
Turnout29.46% of the total population Decrease 16.88 pp[1]
  WinfieldScottHancock.png JamesGarfield.png
Nominee Winfield Scott Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William Hayden English Chester A. Arthur
Electoral vote 3 0
Popular vote 9,613 8,732
Percentage 52.40% 47.60%

President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

The 1880 United States presidential election in Nevada took place on November 2, 1880, as part of the 1880 United States presidential election. Nevada voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

Nevada was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 52.40% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 47.60% of the vote.[2]

Results[edit]

United States presidential election in Nevada, 1880[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 9,613 52.40% 3 100.00%
Republican James A. Garfield of Ohio Chester A. Arthur of New York 8,732 47.60% 0 0.00%
Total 18,345 100.00% 3 100.00%

References[edit]

  1. ^ "1880 Presidential Election Results Nevada Total Population Turnout".
  2. ^ a b c "1880 Presidential Election Results Nevada".