1892 United States presidential election in Nebraska

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United States presidential election in Nebraska, 1892

← 1888 November 8, 1892 1896 →
  Benjamin Harrison, head and shoulders bw photo, 1896.jpg James B. Weaver 1892.jpg StephenGroverCleveland.png
Nominee Benjamin Harrison James B. Weaver Grover Cleveland
Party Republican Populist Democratic
Home state Indiana Iowa New York
Running mate Whitelaw Reid James G. Field Adlai Stevenson I
Electoral vote 8 0 0
Popular vote 87,213 83,134 24,943
Percentage 43.56% 41.53% 12.46%

President before election

Benjamin Harrison

Elected President

Grover Cleveland

The 1892 United States presidential election in Nebraska took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Nebraska voters chose eight electors to the Electoral College, which selected the president and vice president.

Nebraska was won by the Populist nominees, James B. Weaver of Iowa and his running mate James G. Field of Virginia. Weaver and Field defeated the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York.


United States presidential election in Nebraska, 1892[1]
Party Candidate Votes Percentage Electoral votes
Republican Benjamin Harrison (incumbent) 87,213 43.56% 8
People's James Weaver 83,134 41.53% 0
Democratic Grover Cleveland 24,943 12.46% 0
Prohibition John Bidwell 4,902 2.45% 0
Totals 200,192 100.00% 8
Voter turnout


  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Nebraska