1896 United States presidential election in Minnesota

From Wikipedia, the free encyclopedia
Jump to navigation Jump to search
1896 United States presidential election in Minnesota

← 1892 November 3, 1896 1900 →
  William McKinley by Courtney Art Studio, 1896.jpg WilliamJBryan1902.png
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 9 0
Popular vote 193,503 139,735
Percentage 53.77% 40.89%


President before election

Grover Cleveland

Elected President

William McKinley

The 1896 United States presidential election in Minnesota took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

Minnesota was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.


1896 United States presidential election in Minnesota[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 193,503 53.77% 9
Democratic William Jennings Bryan 139,735 40.89% 0
Prohibition Joshua Levering 4,348 1.27% 0
National Democratic John M. Palmer 3,222 0.94% 0
Socialist Labor Charles Matchett 954 0.28% 0
Totals 341,762 100.00% 9
Voter turnout


  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota