1904 United States presidential election in Nebraska

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United States presidential election in Nebraska, 1904

← 1900 November 8, 1904 1908 →
  President Roosevelt - Pach Bros.tif AltonBParker.png Tom E Watson.jpg
Nominee Theodore Roosevelt Alton B. Parker Thomas E. Watson
Party Republican Democratic Populist
Home state New York New York Georgia
Running mate Charles W. Fairbanks Henry G. Davis Thomas Tibbles
Electoral vote 8 0 0
Popular vote 138,558 52,921 20,518
Percentage 61.38% 23.44% 9.09%

President before election

Theodore Roosevelt

Elected President

Theodore Roosevelt

The 1904 United States presidential election in Nebraska took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Nebraska voters chose eight electors to the Electoral College, which selected the president and vice president.

Nebraska was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana.


United States presidential election in Nebraska, 1904[1]
Party Candidate Votes Percentage Electoral votes
Republican Theodore Roosevelt 138,558 61.38% 8
Democratic Alton B. Parker 52,921 23.44% 0
Populist Thomas E. Watson 20,518 9.09% 0
Social Democratic Eugene Debs 7,412 3.28% 0
Prohibition Silas C. Swallow 6,323 2.80% 0
Totals 225,732 100.00% 8
Voter turnout


  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Nebraska