1932 United States presidential election in Iowa

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1932 United States presidential election in Iowa

← 1928 November 8, 1932[1] 1936 →

All 11 Iowa votes to the Electoral College
  FDR in 1933.jpg President Hoover portrait.jpg
Nominee Franklin D. Roosevelt Herbert Hoover
Party Democratic Republican
Home state New York California
Running mate John Nance Garner Charles Curtis
Electoral vote 11 0
Popular vote 598,019 414,433
Percentage 57.7% 40.0%

President before election

Herbert Hoover
Republican

Elected President

Franklin D. Roosevelt
Democratic

The 1932 United States presidential election in Iowa took place on November 8, 1932, as part of the 1932 United States presidential election. Iowa voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Iowa was won by Governor Franklin D. Roosevelt (DNew York), running with Speaker John Nance Garner, with 57.69% of the popular vote, against incumbent President Herbert Hoover (RCalifornia), running with Vice President Charles Curtis, with 39.98% of the popular vote.[3][4]

Results[edit]

1932 United States presidential election in Iowa
Party Candidate Votes %
Democratic Franklin D. Roosevelt 598,019 57.69%
Republican Herbert Hoover (inc.) 414,433 39.98%
Socialist Norman Thomas 20,467 1.97%
Write-in 3,768 0.36%
Total votes 1,036,687 100%

References[edit]

  1. ^ "United States Presidential election of 1932 - Encyclopædia Britannica". Retrieved January 18, 2019.
  2. ^ "1932 Election for the Thirty-seventh Term (1933-37)". Retrieved January 18, 2019.
  3. ^ "1932 Presidential General Election Results - Iowa". Retrieved January 18, 2019.
  4. ^ "The American Presidency Project - Election of 1932". Retrieved January 18, 2019.