1986 Arkansas gubernatorial election

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Arkansas gubernatorial election, 1986

← 1984 November 4, 1986 1990 →
  Bill Clinton.jpg Frank D. White 1995.jpg
Nominee Bill Clinton Frank D. White
Party Democratic Republican
Popular vote 439,802 248,427
Percentage 63.9% 36.1%

Arkansas Gubernatorial Election Results by County, 1986.svg
County Results

Clinton:      50–60%      60–70%      70–80%

White:      50–60%      60–70%

Governor before election

Bill Clinton

Elected Governor

Bill Clinton

The Arkansas gubernatorial election of 1986 was conducted on November 4, 1986, to elect the Governor of Arkansas.

Incumbent Democratic Governor Bill Clinton stood for re-election. He had been elected in 1982 and re-elected in 1984, and sought a third consecutive term and fourth overall (Clinton had been first elected in 1978). His opponent was former Republican Governor Frank D. White, who was seeking to return to the office he had defeated Clinton for in the 1980 election.

After Amendment 63 to the Arkansas state constitution took effect, the term for all Arkansas governors was extended from two years to four. The 1986 election was the first to take place since then, meaning whoever managed to win would become the first elected to a four-year term as Governor of Arkansas.


Clinton won the election with almost 64% of the vote.

Arkansas gubernatorial election, 1986 [1](p18)
Party Candidate Votes % ±
Democratic Bill Clinton 439,802 63.90% +1.35%
Republican Frank D. White 248,427 36.10% -1.35%
Total votes 688,229 100.00
Democratic hold


  1. ^ "Arkansas Election Results 1986" (PDF). Arkansas Secretary of State. Retrieved October 29, 2016.