1988 United States presidential election in Nebraska

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United States presidential election in Nebraska, 1988

← 1984 November 8, 1988 1992 →
  1988 Bush.jpg 1988 Dukakis.jpg
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 5 0
Popular vote 398,447 259,646
Percentage 60.15% 39.20%

NE1988.jpg
County Results
  Dukakis—50-60%
  Bush—<50%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%
  Bush—80-90%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

The 1988 United States presidential election in Nebraska took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Nebraska voters chose 5 electors to the Electoral College, which selected the president and vice president.

Nebraska was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Nebraska weighed in for this election as 7% more Republican than the national average.

Partisan background[edit]

Bush's largely socially conservative rhetoric garnered him much support among social-conservatives nationwide. Seen here at campaign rally in Omaha, Nebraska.

The presidential election of 1988 was a very partisan election for Nebraska, with more than 99% of the electorate voting for either the Democratic or Republican parties, and only 4 political parties appearing on the ballot.[1] As typical for the time, nearly every county in Nebraska turned out primarily for the Republican candidate, with the exception of the Democratic stronghold of Saline County, and a few counties conglomerate with Sioux City, Iowa, in the Northeastern corner of Nebraska, which tended to vote Democratic at this time.

Republican victory[edit]

Bush won the election in Nebraska with a solid 21 point sweep-out landslide. While Nebraska tends to vote conservative, the election results in Nebraska are also reflective of a nationwide political reconsolidation of base for the Republican Party, which took place through the 1980s. Through the passage of some very controversial economic programs, spearheaded by then President Ronald Reagan (called, collectively, "Reaganomics"), the mid-to-late 1980's saw a period of economic growth and stability. The hallmark for Reaganomics was, in part, the wide-scale deregulation of corporate interests, and tax cuts for the wealthy.[2]

Dukakis ran on a socially liberal platform, and advocated for higher economic regulation and environmental protection. Bush, alternatively, ran on a campaign of continuing the social and economic policies of former President Reagan - which gained him much support with social conservatives and people living in rural areas. Additionally, while the economic programs passed under Reagan, and furthered under Bush and Clinton, may have boosted the economy for a brief period, they are criticized by many analysts as "setting the stage" for economic troubles in the United State after 2007, such as the Great Recession.[3]

Results[edit]

United States presidential election in Nebraska, 1988
Party Candidate Votes Percentage Electoral votes
Republican George H. W. Bush 398,447 60.15% 5
Democratic Michael Dukakis 259,646 39.20% 0
Libertarian Ron Paul 2,536 0.38% 0
New Alliance Party Lenora Fulani 1,743 0.26% 0
Totals 662,372 100.0% 5

See also[edit]

References[edit]

  1. ^ "Dave Leip's Atlas of U.S. Presidential Elections". Uselectionatlas.org. Retrieved 2013-07-21.
  2. ^ "Since 1980s, the Kindest of Tax Cuts for the Rich". The New York Times. 2012-01-18. Retrieved 2013-07-21.
  3. ^ Jerry Lanson (2008-11-06). "A historic victory. A changed nation. Now, can Obama deliver?". Christian Science Monitor. Retrieved 2013-07-21.