1990 FIFA World Cup qualification (CONMEBOL)

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The South American (CONMEBOL) zone of qualification for the 1990 FIFA World Cup saw 9 teams competing for 2 direct places at the finals, with one extra place potentially on offer to the winner of a play-off. CONMEBOL member Argentina qualified automatically as reigning World Cup champions.

Format[edit]

Teams were divided into 3 groups of 3 teams each. The teams would play against each other on a home-and-away basis. The 2 group winners with the best record would qualify. The group winner with the worst record would advance to the CONMEBOL / OFC Intercontinental Play-off.

Draw[edit]

The draw for the qualifying groups took place in Zürich, Switzerland on 12 December 1987. During the draw teams were drawn from 3 seeded pots into the 3 qualifying groups.

Pot A Pot B Pot C

 Brazil
 Paraguay
 Uruguay

 Chile
 Colombia
 Peru

 Bolivia
 Ecuador
 Venezuela

Group 1[edit]

Pld W D L GF GA GD Pts
 Uruguay 4 3 0 1 7 2 +5 6
 Bolivia 4 3 0 1 6 5 +1 6
 Peru 4 0 0 4 2 8 −6 0
  Bolivia Peru Uruguay
 BOL 2–1 2–1
 PER 1–2 0–2
 URU 2–0 2–0

Uruguay qualified with the second-best record among the group winners.

Group 2[edit]

Pld W D L GF GA GD Pts
 Colombia 4 2 1 1 5 3 +2 5
 Paraguay 4 2 0 2 6 7 −1 4
 Ecuador 4 1 1 2 4 5 −1 3
  Colombia Ecuador Paraguay
 COL 2–0 2–1
 ECU 0–0 3–1
 PAR 2–1 2–1

Colombia advanced to the CONMEBOL / OFC Intercontinental Play-off with the worst record among the group winners.

Group 3[edit]

Pld W D L GF GA GD Pts
 Brazil 4 3 1 0 13 1 +12 7
 Chile 4 2 1 1 9 4 +5 5
 Venezuela 4 0 0 4 1 18 −17 0
  Brazil Chile Venezuela
 BRA 2–0 6–0
 CHI 1–1 5–0
 VEN 0–4 1–3

Brazil qualified with the best record among the group winners.

Notes[edit]

External links[edit]