2015 ATP World Tour Finals – Doubles

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Doubles
2015 ATP World Tour Finals
ChampionsNetherlands Jean-Julien Rojer
Romania Horia Tecău
Runners-upIndia Rohan Bopanna
Romania Florin Mergea
Final score6–4 , 6–3
Events
Singles Doubles
← 2014 · ATP World Tour Finals · 2016 →

Bob and Mike Bryan were the defending champions, but lost in the semifinals to Jean-Julien Rojer and Horia Tecău.
Rojer and Tecău went on to win the title, defeating Rohan Bopanna and Florin Mergea in the final 6–4, 6–3.

Seeds[edit]

Alternates[edit]

  1. Austria Alexander Peya / Brazil Bruno Soares (Did not play)

Draw[edit]

Key[edit]

Finals[edit]

Semifinals Final
          
8 India Rohan Bopanna
Romania Florin Mergea
6 6
3 Croatia Ivan Dodig
Brazil Marcelo Melo
4 2
8 India Rohan Bopanna
Romania Florin Mergea
4 3
2 Netherlands Jean-Julien Rojer
Romania Horia Tecău
6 6
2 Netherlands Jean-Julien Rojer
Romania Horia Tecău
6 6
1 United States Bob Bryan
United States Mike Bryan
4 4

Group Ashe/Smith[edit]

  United States Bryan
United States Bryan
United Kingdom Murray
Australia Peers
Italy Bolelli
Italy Fognini
India Bopanna
Romania Mergea
RR W–L Set W–L Game W–L Standings
1 United States Bob Bryan
United States Mike Bryan
6–7(5–7), 7–6(7–5), [16–14] 6–3, 6–2 4–6, 3–6 2–1 4–3 33–30 2
4 United Kingdom Jamie Murray
Australia John Peers
7–6(7–5), 6–7(5–7), [14–16] 7–6(7–5), 3–6, [11–9] 3–6, 6–7(5–7) 1–2 3–5 33–39 3
5 Italy Simone Bolelli
Italy Fabio Fognini
3–6, 2–6 6–7(5–7), 6–3, [9–11] 6–4, 1–6, [10–5] 1–2 3–5 25–33 4
8 India Rohan Bopanna
Romania Florin Mergea
6–4, 6–3 6–3, 7–6(7–5) 4–6, 6–1, [5–10] 2–1 5–2 35–24 1

Standings are determined by: 1) Number of wins; 2) Number of matches; 3) In two-players-ties, head-to-head records; 4) In three-players-ties, percentage of sets won, or of games won; 5) Steering Committee decision.

Group Fleming/McEnroe[edit]

  Netherlands Rojer
Romania Tecău
Croatia Dodig
Brazil Melo
France Herbert
France Mahut
Poland Matkowski
Serbia Zimonjić
RR W–L Set W–L Game W–L Standings
2 Netherlands Jean-Julien Rojer
Romania Horia Tecău
6–4, 7–6(7–3) 6–4 , 7–5 6–2, 6–4 3–0 6–0 38–25 1
3 Croatia Ivan Dodig
Brazil Marcelo Melo
4–6, 6–7(3–7) 3–6, 7–6(7–4), [10–7] 3–6, 7–5, [10–6] 2–1 4–4 32–36 2
6 France Pierre-Hugues Herbert
France Nicolas Mahut
4–6 , 5–7 6–3, 6–7(4–7), [7–10] 5–7, 6–3, [10–8] 1–2 3–5 33–34 3
7 Poland Marcin Matkowski
Serbia Nenad Zimonjić
2–6, 4–6 6–3, 5–7, [6–10] 7–5, 3–6, [8–10] 0–3 2–6 27–35 4

Standings are determined by: 1) Number of wins; 2) Number of matches; 3) In two-players-ties, head-to-head records; 4) In three-players-ties, percentage of sets won, or of games won; 5) Steering Committee decision.

References[edit]