2018 Silicon Valley Classic – Doubles

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Doubles
2018 Silicon Valley Classic
ChampionsChinese Taipei Latisha Chan
Czech Republic Květa Peschke
Runners-upUkraine Lyudmyla Kichenok
Ukraine Nadiia Kichenok
Final score6–4, 6–1
Events
Singles Doubles
← 2017 · Silicon Valley Classic · 2019 →

Abigail Spears and CoCo Vandeweghe were the defending champions, but chose not to participate this year.

Latisha Chan and Květa Peschke won the title, defeating Lyudmyla and Nadiia Kichenok in the final, 6–4, 6–1.

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First Round Quarterfinals Semifinals Final
1 Chinese Taipei L Chan
Czech Republic K Peschke
w/o
Paraguay V Cepede Royg
United States I Falconi
4 1 United States S Kenin
Belarus A Sabalenka
United States S Kenin
Belarus A Sabalenka
6 6 1 Chinese Taipei L Chan
Czech Republic K Peschke
6 6
4 Japan M Kato
Japan M Ninomiya
1 7 [10] 4 Japan M Kato
Japan M Ninomiya
1 4
Poland M Fręch
United States M Sanchez
6 5 [4] 4 Japan M Kato
Japan M Ninomiya
6 6
Ukraine K Bondarenko
Russia V Savinykh
4 4 Spain G García Pérez
Australia P Hon
4 2
Spain G García Pérez
Australia P Hon
6 6 1 Chinese Taipei L Chan
Czech Republic K Peschke
6 6
Argentina M Irigoyen
United States D Krawczyk
3 3 3 Ukraine L Kichenok
Ukraine N Kichenok
4 1
Russia A Blinkova
Russia N Dzalamidze
6 6 Russia A Blinkova
Russia N Dzalamidze
6 2 [6]
United States K Christian
United States S Santamaria
6 3 [7] 3 Ukraine L Kichenok
Ukraine N Kichenok
1 6 [10]
3 Ukraine L Kichenok
Ukraine N Kichenok
4 6 [10] 3 Ukraine L Kichenok
Ukraine N Kichenok
6 3 [10]
United States J Cako
Germany N Geuer
3 2 2 Romania M Buzărnescu
United Kingdom H Watson
4 6 [8]
United Kingdom J Konta
China S Zhang
6 6 United Kingdom J Konta
China S Zhang
5 2
WC United States T Culibrk
France S Gauvain
3 3 2 Romania M Buzărnescu
United Kingdom H Watson
7 6
2 Romania M Buzărnescu
United Kingdom H Watson
6 6

References[edit]