1856 Belgian general election
Appearance
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54 of the 108 seats in the Chamber of Representatives 55 seats needed for a majority | |||||||||||||||||||
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Partial general elections were held in Belgium on 10 June 1856.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholics, who won 63 of the 108 seats.[2] Voter turnout was 60.6%, although only 43,573 people were eligible to vote.
Under the alternating system, Chamber elections were only held in four out of the nine provinces: East Flanders, Hainaut, Liège and Limburg. Thus, 54 of the 108 Chamber seats were up for election.
Results
Chamber of Representatives
Party | Votes | % | Seats | ||
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Won | Total | +/– | |||
Catholics | 15,168 | 54.9 | 33 | 63 | +9 |
Liberal Party | 12,472 | 45.1 | 21 | 45 | –9 |
Invalid/blank votes | 3,621 | – | – | – | – |
Total | 27,640 | 100 | 54 | 108 | 0 |
Registered voters/turnout | 45,573 | 60.6 | – | – | – |
Source: Mackie & Rose,[3] Sternberger et al. |