Belgian general election, 1890

From Wikipedia, the free encyclopedia
Jump to: navigation, search
Belgian general election, 1890
Belgium
1888 ←
10 June 1890 (1890-06-10) → 1892

All 138 seats in the Chamber of Representatives
70 seats needed for a majority
  First party Second party
 
Party Catholic Liberal
Last election 98 seats 40 seats
Seats won 94 44
Seat change Decrease4 Increase4
State Coat of Arms of Belgium.svg
This article is part of a series on the
politics and government of
Belgium
Constitution
Foreign relations

General elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2] Voter turnout was 73.0%, although only 59,452 people were eligible to vote.[2]

Results[edit]

Chamber of Representatives[edit]

Party Votes % Seats +/–
Catholic Party 94 –4
Liberal Party 44 +4
Total 138 0
Sternberger et al.

References[edit]

  1. ^ Codebook Constituency-level Elections Archive, 2003
  2. ^ a b c Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105