# Binet–Cauchy identity

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In algebra, the Binet–Cauchy identity, named after Jacques Philippe Marie Binet and Augustin-Louis Cauchy, states that [1]

${\displaystyle {\biggl (}\sum _{i=1}^{n}a_{i}c_{i}{\biggr )}{\biggl (}\sum _{j=1}^{n}b_{j}d_{j}{\biggr )}={\biggl (}\sum _{i=1}^{n}a_{i}d_{i}{\biggr )}{\biggl (}\sum _{j=1}^{n}b_{j}c_{j}{\biggr )}+\sum _{1\leq i

for every choice of real or complex numbers (or more generally, elements of a commutative ring). Setting ai = ci and bj = dj, it gives the Lagrange's identity, which is a stronger version of the Cauchy–Schwarz inequality for the Euclidean space ${\displaystyle \scriptstyle \mathbb {R} ^{n}}$.

## The Binet–Cauchy identity and exterior algebra

When n = 3 the first and second terms on the right hand side become the squared magnitudes of dot and cross products respectively; in n dimensions these become the magnitudes of the dot and wedge products. We may write it

${\displaystyle (a\cdot c)(b\cdot d)=(a\cdot d)(b\cdot c)+(a\wedge b)\cdot (c\wedge d)\,}$

where a, b, c, and d are vectors. It may also be written as a formula giving the dot product of two wedge products, as

${\displaystyle (a\wedge b)\cdot (c\wedge d)=(a\cdot c)(b\cdot d)-(a\cdot d)(b\cdot c).\,}$

In the special case of unit vectors a=c and b=d, the formula yields

${\displaystyle |a\wedge b|^{2}=|a|^{2}|b|^{2}-|a\cdot b|^{2}.\,}$

When both vectors are unit vectors, we obtain the usual relation

${\displaystyle 1=\cos ^{2}(\phi )+\sin ^{2}(\phi )}$

where φ is the angle between the vectors.

## Proof

Expanding the last term,

${\displaystyle \sum _{1\leq i
${\displaystyle =\sum _{1\leq i

where the second and fourth terms are the same and artificially added to complete the sums as follows:

${\displaystyle =\sum _{i=1}^{n}\sum _{j=1}^{n}a_{i}c_{i}b_{j}d_{j}-\sum _{i=1}^{n}\sum _{j=1}^{n}a_{i}d_{i}b_{j}c_{j}.}$

This completes the proof after factoring out the terms indexed by i.

## Generalization

A general form, also known as the Cauchy–Binet formula, states the following: Suppose A is an m×n matrix and B is an n×m matrix. If S is a subset of {1, ..., n} with m elements, we write AS for the m×m matrix whose columns are those columns of A that have indices from S. Similarly, we write BS for the m×m matrix whose rows are those rows of B that have indices from S. Then the determinant of the matrix product of A and B satisfies the identity

${\displaystyle \det(AB)=\sum _{\scriptstyle S\subset \{1,\ldots ,n\} \atop \scriptstyle |S|=m}\det(A_{S})\det(B_{S}),}$

where the sum extends over all possible subsets S of {1, ..., n} with m elements.

We get the original identity as special case by setting

${\displaystyle A={\begin{pmatrix}a_{1}&\dots &a_{n}\\b_{1}&\dots &b_{n}\end{pmatrix}},\quad B={\begin{pmatrix}c_{1}&d_{1}\\\vdots &\vdots \\c_{n}&d_{n}\end{pmatrix}}.}$

## In-line notes and references

1. ^ Eric W. Weisstein (2003). "Binet-Cauchy identity". CRC concise encyclopedia of mathematics (2nd ed.). CRC Press. p. 228. ISBN 1-58488-347-2.