Bloom Township, Seneca County, Ohio

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Bloom Township, Ohio
Location of Bloom Township in Seneca County.
Location of Bloom Township in Seneca County.
Coordinates: 41°2′46″N 83°0′46″W / 41.04611°N 83.01278°W / 41.04611; -83.01278Coordinates: 41°2′46″N 83°0′46″W / 41.04611°N 83.01278°W / 41.04611; -83.01278
Country United States
State Ohio
County Seneca
 • Total 36.5 sq mi (94.4 km2)
 • Land 36.4 sq mi (94.2 km2)
 • Water 0.1 sq mi (0.2 km2)
Elevation[1] 912 ft (278 m)
Population (2000)
 • Total 1,937
 • Density 53.3/sq mi (20.6/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 39-07006[2]
GNIS feature ID 1086942[1]

Bloom Township is one of the fifteen townships of Seneca County, Ohio, United States. The 2000 census found 1,937 people in the township, 892 of whom lived in the unincorporated portions of the township.[3]


Located in the southeastern part of the county, it borders the following townships:

The village of Bloomville is located in central Bloom Township.

Name and history[edit]

Bloom Township was organized in 1824.[4] It was named from its scenic rustic setting.[5]

Statewide, other Bloom Townships are located in Fairfield, Morgan, Scioto, and Wood counties.


The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[6] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.


External links[edit]