Brownsdale, Florida

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Brownsdale, Florida
Brownsdale, Florida is located in Florida
Brownsdale, Florida
Brownsdale, Florida
Brownsdale, Florida is located in the United States
Brownsdale, Florida
Brownsdale, Florida
Coordinates: 30°52′57″N 87°13′32″W / 30.88250°N 87.22556°W / 30.88250; -87.22556Coordinates: 30°52′57″N 87°13′32″W / 30.88250°N 87.22556°W / 30.88250; -87.22556
CountryUnited States
StateFlorida
CountySanta Rosa
Area
 • Total8.892 sq mi (23.03 km2)
 • Land8.700 sq mi (22.53 km2)
 • Water0.192 sq mi (0.50 km2)
Elevation
243 ft (74 m)
Population
 • Total471
 • Density53/sq mi (20/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code(s)850
GNIS feature ID279497[2]

Brownsdale is an unincorporated community and census-designated place in Santa Rosa County, Florida, United States. Its population was 471 as of the 2010 census.[1]

Geography[edit]

According to the U.S. Census Bureau, the community has an area of 8.892 square miles (23.03 km2); 8.700 square miles (22.53 km2) of its area is land, and 0.192 square miles (0.50 km2) is water.[1]

References[edit]

  1. ^ a b c d "2010 Census Gazetteer Files - Places: Florida". U.S. Census Bureau. Retrieved March 25, 2017.
  2. ^ "Brownsdale". Geographic Names Information System. United States Geological Survey.