# Central binomial coefficient

Pascal's triangle, rows 0 through 7. The numbers in the central column are the central binomial coefficients.

In mathematics the nth central binomial coefficient is the particular binomial coefficient

${\displaystyle {2n \choose n}={\frac {(2n)!}{(n!)^{2}}}{\text{ for all }}n\geq 0.}$

They are called central since they show up exactly in the middle of the even-numbered rows in Pascal's triangle. The first few central binomial coefficients starting at n = 0 are:

1, 2, 6, 20, 70, 252, 924, 3432, 12870, 48620, ...; (sequence A000984 in the OEIS)

## Properties

The central binomial coefficients have ordinary generating function

${\displaystyle {\frac {1}{\sqrt {1-4x}}}=1+2x+6x^{2}+20x^{3}+70x^{4}+252x^{5}+\cdots }$

and exponential generating function

${\displaystyle \sum _{n=0}^{\infty }{\binom {2n}{n}}{\frac {x^{n}}{n!}}=e^{2x}I_{0}(2x),}$

where I0 is a modified Bessel function of the first kind.[1]

They also satisfy the recurrence

${\displaystyle {\binom {2(n+1)}{n+1}}={\frac {4n+2}{n+1}}\cdot {\binom {2n}{n}}.}$

The Wallis product can be written in asymptotic form for the central binomial coefficient:

${\displaystyle {2n \choose n}\sim {\frac {4^{n}}{\sqrt {\pi n}}}.}$

The latter can also be easily established by means of Stirling's formula. On the other hand, it can also be used as a means to determine the constant ${\displaystyle {\sqrt {2\pi }}}$ in front of the Stirling formula, by comparison.

Simple bounds that immediately follow from ${\displaystyle 4^{n}=(1+1)^{2n}=\sum _{k=0}^{2n}{\binom {2n}{k}}}$ are

${\displaystyle {\frac {4^{n}}{2n+1}}\leq {2n \choose n}\leq 4^{n}{\text{ for all }}n\geq 1}$

Some better bounds are[2]

${\displaystyle {\frac {4^{n}}{\sqrt {4n}}}\leq {2n \choose n}\leq {\frac {4^{n}}{\sqrt {3n+1}}}{\text{ for all }}n\geq 1}$

and, if more accuracy is required,

${\displaystyle {2n \choose n}={\frac {4^{n}}{\sqrt {\pi n}}}\left(1-{\frac {c_{n}}{n}}\right){\text{ where }}{\frac {1}{9}} for all ${\displaystyle n\geq 1.}$[citation needed]

The only central binomial coefficient that is odd is 1. More specifically, the number of factors of 2 in ${\displaystyle {\binom {2n}{n}}}$ is equal to the number of ones in the binary representation of n.[3]

By the Erdős squarefree conjecture, proven in 1996, no central binomial coefficient with n > 4 is squarefree.

The central binomial coefficient ${\displaystyle {2n \choose n}}$ equals the sum of the squares of the elements in row n of Pascal's triangle.[1]

## Related sequences

The closely related Catalan numbers Cn are given by:

${\displaystyle C_{n}={\frac {1}{n+1}}{2n \choose n}={2n \choose n}-{2n \choose n+1}{\text{ for all }}n\geq 0.}$

A slight generalization of central binomial coefficients is to take them as ${\displaystyle {\frac {\Gamma (2n+1)}{\Gamma (n+1)^{2}}}={\frac {1}{n\mathrm {B} (n+1,n)}}}$, with appropriate real numbers n, where ${\displaystyle \Gamma (x)}$ is the gamma function and ${\displaystyle \mathrm {B} (x,y)}$ is the beta function.

The powers of two that divide the central binomial coefficients are given by Gould's sequence, whose nth element is the number of odd integers in row n of Pascal's triangle.

## References

1. ^ a b Sloane, N.J.A. (ed.). "Sequence A000984 (Central binomial coefficients)". The On-Line Encyclopedia of Integer Sequences. OEIS Foundation.
2. ^ Kazarinoff, N.D. Geometric inequalities, New York: Random House, 1961
3. ^ Sloane, N.J.A. (ed.). "Sequence A000120". The On-Line Encyclopedia of Integer Sequences. OEIS Foundation.
• Koshy, Thomas (2008), Catalan Numbers with Applications, Oxford University Press, ISBN 978-0-19533-454-8.