De Soto, Nebraska

From Wikipedia, the free encyclopedia
Jump to: navigation, search
De Soto, Nebraska
Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W / 41.5011528; -96.0567083Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W / 41.5011528; -96.0567083
Country United States
State Nebraska
County Washington
Elevation 1,007 ft (307 m)
Time zone Central (CST) (UTC-6)
 • Summer (DST) CDT (UTC-5)
Area code(s) 402

De Soto is an unincorporated community in Washington County, Nebraska, United States.[1] It was named in honor of the sixteenth-century Spanish explorer, Hernando De Soto.[2] De Soto was founded in 1855 and served as the county seat from 1858-1866. During its heyday, the town hosted many flourishing new businesses: hotels, saloons, stores, newspapers and banks.[3]

De Soto contains farmland with about three families residing there.[4]

References[edit]

External links[edit]