# Euclid's theorem

Field Number theory Euclid c. 300 BCE Dirichlet's theorem on arithmetic progressionsPrime number theorem

Euclid's theorem is a fundamental statement in number theory that asserts that there are infinitely many prime numbers. It was first proved by Euclid in his work Elements. There are several proofs of the theorem.

## Euclid's proof

Euclid offered a proof published in his work Elements (Book IX, Proposition 20),[1] which is paraphrased here.[2]

Consider any finite list of prime numbers p1p2, ..., pn. It will be shown that at least one additional prime number not in this list exists. Let P be the product of all the prime numbers in the list: P = p1p2...pn. Let q = P + 1. Then q is either prime or not:

• If q is prime, then there is at least one more prime that is not in the list.
• If q is not prime, then some prime factor p divides q. If this factor p were in our list, then it would divide P (since P is the product of every number in the list); but p also divides P + 1 = q, as just stated. If p divides P and also q, then p must also divide the difference[3] of the two numbers, which is (P + 1) − P or just 1. Since no prime number divides 1, p cannot be on the list. This means that at least one more prime number exists beyond those in the list.

This proves that for every finite list of prime numbers there is a prime number not in the list.[4] In the original work, as Euclid had no way of writing an arbitrary list of primes, he used a method that he frequently applied, that is, the method of generalizable example. Namely, he picks just three primes and using the general method outlined above, proves that he can always find an additional prime. Euclid presumably assumes that his readers are convinced that a similar proof will work, no matter how many primes are originally picked.[5]

Euclid is often erroneously reported to have proved this result by contradiction beginning with the assumption that the finite set initially considered contains all prime numbers,[6] though it is actually a proof by cases, a direct proof method. The philosopher Torkel Franzén, in a book on logic, states, "Euclid's proof that there are infinitely many primes is not an indirect proof [...] The argument is sometimes formulated as an indirect proof by replacing it with the assumption 'Suppose q1, ... qn are all the primes'. However, since this assumption isn't even used in the proof, the reformulation is pointless."[7]

### Variations

Several variations on Euclid's proof exist, including the following:

The factorial n! of a positive integer n is divisible by every integer from 2 to n, as it is the product of all of them. Hence, n! + 1 is not divisible by any of the integers from 2 to n, inclusive (it gives a remainder of 1 when divided by each). Hence n! + 1 is either prime or divisible by a prime larger than n. In either case, for every positive integer n, there is at least one prime bigger than n. The conclusion is that the number of primes is infinite.[8]

## Euler's proof

Another proof, by the Swiss mathematician Leonhard Euler, relies on the fundamental theorem of arithmetic: that every integer has a unique prime factorization. If P is the set of all prime numbers, Euler wrote that:

${\displaystyle \prod _{p\in P}{\frac {1}{1-{\frac {1}{p}}}}=\prod _{p\in P}\sum _{k\geq 0}{\frac {1}{p^{k}}}=\sum _{n}{\frac {1}{n}}.}$

The first equality is given by the formula for a geometric series in each term of the product. The second equality is a special case of the Euler product formula for the Riemann zeta function. To show this, distribute the product over the sum:

{\displaystyle {\begin{aligned}\prod _{p\in P}\sum _{k\geq 0}{\frac {1}{p^{k}}}&=\sum _{k\geq 0}{\frac {1}{2^{k}}}\times \sum _{k\geq 0}{\frac {1}{3^{k}}}\times \sum _{k\geq 0}{\frac {1}{5^{k}}}\times \sum _{k\geq 0}{\frac {1}{7^{k}}}\times \cdots \\[8pt]&=\sum _{k,\ell ,m,n,\ldots \geq 0}{\frac {1}{2^{k}3^{\ell }5^{m}7^{n}\cdots }}=\sum _{n}{\frac {1}{n}}\end{aligned}}}

In the result, every product of primes appears exactly once and so by the fundamental theorem of arithmetic the sum is equal to the sum over all integers.

The sum on the right is the harmonic series, which diverges. Thus the product on the left must also diverge. Since each term of the product is finite, the number of terms must be infinite; therefore, there is an infinite number of primes.

## Bertrand–Chebyshev proof

In number theory, Bertrand's postulate is a theorem stating that for any integer ${\displaystyle n>1}$, there always exists at least one prime number such that

${\displaystyle n

Bertrand–Chebyshev theorem can also be stated as a relationship with ${\displaystyle \pi (x)}$, where ${\displaystyle \pi (x)}$ is the prime counting function (number of primes less than or equal to ${\displaystyle x\,}$):

${\displaystyle \pi (x)-\pi ({\tfrac {x}{2}})\geq 1}$, for all ${\displaystyle x\geq 2}$.

This statement was first conjectured in 1845 by Joseph Bertrand[9] (1822–1900). Bertrand himself verified his statement for all numbers in the interval [2, 3 × 106]. His conjecture was completely proved by Chebyshev (1821–1894) in 1852[10] and so the postulate is also called the Bertrand–Chebyshev theorem or Chebyshev's theorem.

## Erdős's proof

Paul Erdős gave a proof[11] that also relies on the fundamental theorem of arithmetic. Every positive integer has a unique factorization into a square-free number and a square number rs2. For example, 75,600 = 24 33 52 71 = 21 ⋅ 602.

Let N be a positive integer, and let k be the number of primes less than or equal to N. Call those primes p1, ... , pk. Any positive integer which is less than or equal to N can then be written in the form

${\displaystyle \left(p_{1}^{e_{1}}p_{2}^{e_{2}}\cdots p_{k}^{e_{k}}\right)s^{2},}$

where each ei is either 0 or 1. There are 2k ways of forming the square-free part of a. And s2 can be at most N, so sN. Thus, at most 2k N numbers can be written in this form. In other words,

${\displaystyle N\leq 2^{k}{\sqrt {N}}.}$

Or, rearranging, k, the number of primes less than or equal to N, is greater than or equal to 1/2log2 N. Since N was arbitrary, k can be as large as desired by choosing N appropriately.

## Furstenberg's proof

In the 1950s, Hillel Furstenberg introduced a proof by contradiction using point-set topology.[12]

Define a topology on the integers Z, called the evenly spaced integer topology, by declaring a subset U ⊆ Z to be an open set if and only if it is either the empty set, ∅, or it is a union of arithmetic sequences S(ab) (for a ≠ 0), where

${\displaystyle S(a,b)=\{an+b\mid n\in \mathbb {Z} \}=a\mathbb {Z} +b.}$

Then a contradiction follows from the property that a finite set of integers cannot be open and the property that the basis sets S(ab) are both open and closed, since

${\displaystyle \mathbb {Z} \setminus \{-1,+1\}=\bigcup _{p\mathrm {\,prime} }S(p,0)}$

cannot be closed because its complement is finite, but is closed since it is a finite union of closed sets.

## Some recent proofs

### Proof using the inclusion-exclusion principle

Juan Pablo Pinasco has written the following proof.[13]

Let p1, ..., pN be the smallest N primes. Then by the inclusion–exclusion principle, the number of positive integers less than or equal to x that are divisible by one of those primes is

{\displaystyle {\begin{aligned}1+\sum _{i}\left\lfloor {\frac {x}{p_{i}}}\right\rfloor -\sum _{i

Dividing by x and letting x → ∞ gives

${\displaystyle \sum _{i}{\frac {1}{p_{i}}}-\sum _{i

This can be written as

${\displaystyle 1-\prod _{i=1}^{N}\left(1-{\frac {1}{p_{i}}}\right).\qquad (3)}$

If no other primes than p1, ..., pN exist, then the expression in (1) is equal to ${\displaystyle \lfloor x\rfloor }$ and the expression in (2) is equal to 1, but clearly the expression in (3) is not equal to 1. Therefore, there must be more primes than  p1, ..., pN.

### Proof using de Polignac's formula

In 2010, Junho Peter Whang published the following proof by contradiction.[14] Let k be any positive integer. Then according to de Polignac's formula (actually due to Legendre)

${\displaystyle k!=\prod _{p{\text{ prime}}}p^{f(p,k)}}$

where

${\displaystyle f(p,k)=\left\lfloor {\frac {k}{p}}\right\rfloor +\left\lfloor {\frac {k}{p^{2}}}\right\rfloor +\cdots .}$
${\displaystyle f(p,k)<{\frac {k}{p}}+{\frac {k}{p^{2}}}+\cdots ={\frac {k}{p-1}}\leq k.}$

But if only finitely many primes exist, then

${\displaystyle \lim _{k\to \infty }{\frac {\left(\prod _{p}p\right)^{k}}{k!}}=0,}$

(the numerator of the fraction would grow singly exponentially while by Stirling's approximation the denominator grows more quickly than singly exponentially), contradicting the fact that for each k the numerator is greater than or equal to the denominator.

### Proof by construction

Filip Saidak gave the following proof by construction, which does not use reductio ad absurdum[15] or Euclid's Lemma (that if a prime p divides ab then it must divide a or b).

Since each natural number (> 1) has at least one prime factor, and two successive numbers n and (n + 1) have no factor in common, the product n(n + 1) has more different prime factors than the number n itself.  So the chain of pronic numbers:
1×2 = 2 {2},    2×3 = 6 {2, 3},    6×7 = 42 {2, 3, 7},    42×43 = 1806 {2, 3, 7, 43},    1806×1807 = 3263442 {2, 3, 7, 43, 13, 139}, · · ·
provides a sequence of unlimited growing sets of primes.

### Proof using the irrationality of π

Representing the Leibniz formula for π as an Euler product gives[16]

${\displaystyle {\frac {\pi }{4}}={\frac {3}{4}}\times {\frac {5}{4}}\times {\frac {7}{8}}\times {\frac {11}{12}}\times {\frac {13}{12}}\times {\frac {17}{16}}\times {\frac {19}{20}}\times {\frac {23}{24}}\times {\frac {29}{28}}\times {\frac {31}{32}}\times \cdots }$

The numerators of this product are the odd prime numbers, and each denominator is the multiple of four nearest to the numerator.

If there were finitely many primes this formula would show that π is a rational number whose denominator is the product of all multiples of 4 that are one more or less than a prime number, contradicting the fact that π is irrational.

### Proof using information theory

Alexander Shen and others[who?] have presented a proof that uses incompressibility:[17]

Suppose there were only k primes (p1... pk). By the fundamental theorem of arithmetic, any positive integer n could then be represented as:

${\displaystyle n={p_{1}}^{e_{1}}{p_{2}}^{e_{2}}\cdots {p_{k}}^{e_{k}},}$

where the non-negative integer exponents ei together with the finite-sized list of primes are enough to reconstruct the number. Since ${\displaystyle p_{i}\geq 2}$ for all i, it follows that all ${\displaystyle e_{i}\leq \lg n}$ (where ${\displaystyle \lg }$ denotes the base-2 logarithm).

This yields an encoding for n of the following size (using big O notation):

${\displaystyle O({\text{prime list size}}+k\lg \lg n)=O(\lg \lg n)}$ bits.

This is a much more efficient encoding than representing n directly in binary, which takes ${\displaystyle N=O(\lg n)}$ bits. An established result in lossless data compression states that one cannot generally compress N bits of information into fewer than N bits. The representation above violates this by far when n is large enough since ${\displaystyle \lg \lg n=o(\lg n)}$.

Therefore, the number of primes must not be finite.

## Stronger results

The theorems in this section simultaneously imply Euclid's theorem and other results.

### Dirichlet's theorem on arithmetic progressions

Dirichlet's theorem states that for any two positive coprime integers a and d, there are infinitely many primes of the form a + nd, where n is also a positive integer. In other words, there are infinitely many primes that are congruent to a modulo d.

### Prime number theorem

Let π(x) be the prime-counting function that gives the number of primes less than or equal to x, for any real number x. The prime number theorem then states that x / log x is a good approximation to π(x), in the sense that the limit of the quotient of the two functions π(x) and x / log x as x increases without bound is 1:

${\displaystyle \lim _{x\rightarrow \infty }{\frac {\pi (x)}{x/\ln(x)}}=1.}$

Using asymptotic notation this result can be restated as

${\displaystyle \pi (x)\sim {\frac {x}{\log x}}.}$

This yields Euclid's theorem, since ${\displaystyle \lim _{x\rightarrow \infty }{\frac {x}{\log x}}=\infty .}$

## Notes and references

1. ^ James Williamson (translator and commentator), The Elements of Euclid, With Dissertations, Clarendon Press, Oxford, 1782, page 63.
2. ^ Ore, Oystein (1988) [1948], Number Theory and its History, Dover, p. 65
3. ^ In general, for any integers a, b, c if ${\displaystyle a\mid b}$ and ${\displaystyle a\mid c}$, then ${\displaystyle a\mid (b-c)}$. For more information, see Divisibility.
4. ^ The exact formulation of Euclid's assertion is: "The prime numbers are more numerous than any proposed multitude of prime numbers".
5. ^ Katz, Victor J. (1998), A History of Mathematics/ an Introduction (2nd ed.), Addison Wesley Longman, p. 87
6. ^ Michael Hardy and Catherine Woodgold, "Prime Simplicity", Mathematical Intelligencer, volume 31, number 4, fall 2009, pages 44–52.
7. ^ Franzén, Torkel (2004), Inexhaustibility: A Non-exhaustive Treatment, A K Peters, Ltd, p. 101
8. ^ Bostock, Linda; Chandler, Suzanne; Rourke, C. (2014-11-01). Further Pure Mathematics. Nelson Thornes. p. 168. ISBN 9780859501033.
9. ^ Bertrand, Joseph (1845), "Mémoire sur le nombre de valeurs que peut prendre une fonction quand on y permute les lettres qu'elle renferme.", Journal de l'École Royale Polytechnique (in French), 18 (Cahier 30): 123–140.
10. ^ Tchebychev, P. (1852), "Mémoire sur les nombres premiers." (PDF), Journal de mathématiques pures et appliquées, Série 1 (in French): 366–390. (Proof of the postulate: 371-382). Also see Mémoires de l'Académie Impériale des Sciences de St. Pétersbourg, vol. 7, pp.15-33, 1854
11. ^ Havil, Julian (2003). Gamma: Exploring Euler's Constant. Princeton University Press. pp. 28-29. ISBN 0-691-09983-9.
12. ^ Furstenberg, Harry (1955). "On the infinitude of primes". American Mathematical Monthly. 62 (5): 353. doi:10.2307/2307043. JSTOR 2307043. MR 0068566.
13. ^ Juan Pablo Pinasco, "New Proofs of Euclid's and Euler's theorems", American Mathematical Monthly, volume 116, number 2, February, 2009, pages 172–173.
14. ^ Junho Peter Whang, "Another Proof of the Infinitude of the Prime Numbers", American Mathematical Monthly, volume 117, number 2, February 2010, page 181.
15. ^ Saidak, Filip (December 2006). "A New Proof of Euclid's Theorem". American Mathematical Monthly. 113 (10). doi:10.2307/27642094.
16. ^ Debnath, Lokenath (2010), The Legacy of Leonhard Euler: A Tricentennial Tribute, World Scientific, p. 214, ISBN 9781848165267.
17. ^ Shen, Alexander (2016), Kolmogorov complexity and algorithmic randomness (PDF), AMS, p. 245