For devices such as operational amplifiers that are designed to have a simple one-pole frequency response, the gain–bandwidth product is nearly independent of the gain at which it is measured; in such devices the gain–bandwidth product will also be equal to the unity-gain bandwidth of the amplifier (the bandwidth within which the amplifier gain is at least 1). For an amplifier in which negative feedback reduces the gain to below the open-loop gain, the gain–bandwidth product of the closed-loop amplifier will be approximately equal to that of the open-loop amplifier. According to S. Srinivasan, "The parameter characterizing the frequency dependence of the operational amplifier gain is the finite gain–bandwidth product (GB)."
Relevance to design
This quantity is commonly specified for operational amplifiers, and allows circuit designers to determine the maximum gain that can be extracted from the device for a given frequency (or bandwidth) and vice versa.
When adding LC circuits to the input and output of an amplifier the gain rises and the bandwidth decreases, but the product is generally bounded by the gain–bandwidth product.
If the GBWP of an operational amplifier is 1 MHz, it means that the gain of the device falls to unity at 1 MHz. Hence, when the device is wired for unity gain, it will work up to 1 MHz (GBWP = gain × bandwidth, therefore if BW = 1 MHz, then gain = 1) without excessively distorting the signal. The same device when wired for a gain of 10 will work only up to 100 kHz, in accordance with the GBW product formula. Further, if the minimum frequency of operation is 1 Hz, then the maximum gain that can be extracted from the device is 1×106.
We can also analytically show that for GBWP is constant.
Let be a first-order transfer function given by:
We will show that:
Proof: We will expand using Taylor series  and retain the constant and first term, to obtain:
Note that the error in this case is only about 2%, for the constant term, and using the second term, , the error drops to .06%.
For transistors, the current-gain–bandwidth product is known as the fT or transition frequency. It is calculated from the low-frequency (a few kilohertz) current gain under specified test conditions, and the cutoff frequency at which the current gain drops by 3 decibels (70% amplitude); the product of these two values can be thought of as the frequency at which the current gain would drop to 1, and the transistor current gain between the cutoff and transition frequency can be estimated by dividing fT by the frequency. Usually, transistors must be applied at frequencies well below fT to be useful as amplifiers and oscillators. In a bipolar junction transistor, frequency response declines owing to the internal capacitance of the junctions. The transition frequency varies with collector current, reaching a maximum for some value and declining for greater or lesser collector current.
- Cox, James (2002). Fundamentals of linear electronics: integrated and discrete. Albany: Delmar. p. 354. ISBN 0-7668-3018-7.
- U. A. Bakshi and A. P. Godse (2009). Analog And Digital Electronics. Technical Publications. pp. 2–5. ISBN 978-81-8431-708-4.
- Srinivasan, S. "A universal compensation scheme for active filters." International Journal of Electronics 42.2 (Feb. 1977): 141. Science & Technology Collection. EBSCO. Dallas Public Library <http://www.dplibrary.org Archived 2011-06-30 at the Wayback Machine.>, Dallas, TX, USA. retrieved 31 July 2009 from <http://search.ebscohost.com/login.aspx?direct=true&db=syh&AN=5259750&site=ehost-live>.
- Stanley William Amos and Mike James (2000). Principles of transistor circuits: introduction to the design of amplifiers, receivers, and digital (9th ed.). Newnes. p. 169. ISBN 978-0-7506-4427-3.
- M K Achuthan and K N Bhat (2007). Fundamentals of semiconductor devices. Tata McGraw-Hill Education. p. 408. ISBN 978-0-07-061220-4.
- Martin Hartley Jones A practical introduction to electronic circuits, Cambridge University Press, 1995 ISBN 0-521-47879-0 page 148
- "Op-amp gain-bandwidth-product" masteringelectronicsdesign.com