Hobart Township, Lake County, Indiana
Hobart Township | |
---|---|
Coordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W | |
Country | United States |
State | Indiana |
County | Lake |
Government | |
• Type | Indiana township |
Area | |
• Total | 25.98 sq mi (67.3 km2) |
• Land | 25.47 sq mi (66.0 km2) |
• Water | 0.51 sq mi (1.3 km2) |
Elevation | 627 ft (191 m) |
Population | |
• Total | 40,652 |
• Density | 1,547.4/sq mi (597.5/km2) |
FIPS code | 18-34132[3] |
GNIS feature ID | 453414 |
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[4]
Geography[edit]
According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water.[4]
References[edit]
- ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "Census Bureau profile: Hobart Township, Lake County, Indiana". United States Census Bureau. May 2023. Retrieved March 15, 2024.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
External links[edit]