Hoseynabad, Khodabandeh

From Wikipedia, the free encyclopedia
  (Redirected from Hosein Abad Khodabandehloo)
Jump to: navigation, search
Hoseynabad
حسين اباد
village
Hoseynabad is located in Iran
Hoseynabad
Hoseynabad
Coordinates: 35°54′28″N 48°38′08″E / 35.90778°N 48.63556°E / 35.90778; 48.63556Coordinates: 35°54′28″N 48°38′08″E / 35.90778°N 48.63556°E / 35.90778; 48.63556
Country  Iran
Province Zanjan
County Khodabandeh
Bakhsh Central
Rural District Khararud
Population (2006)
 • Total 452
Time zone IRST (UTC+3:30)
 • Summer (DST) IRDT (UTC+4:30)

Hoseynabad (Persian: حسين اباد‎‎, also Romanized as Ḩoseynābād; also knowna s Hosein Abad Khodabandehloo and Husainābād)[1] is a village in Khararud Rural District, in the Central District of Khodabandeh County, Zanjan Province, Iran. At the 2006 census, its population was 452, in 96 families.[2]

References[edit]

  1. ^ Hoseynabad can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3066934" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)". Islamic Republic of Iran. Archived from the original (Excel) on 2011-11-11.