Humboldt Township, Humboldt County, Iowa

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Humboldt Township
Township
Location in Humboldt County
Location in Humboldt County
Coordinates: 42°51′40″N 91°09′14″W / 42.86111°N 91.15389°W / 42.86111; -91.15389Coordinates: 42°51′40″N 91°09′14″W / 42.86111°N 91.15389°W / 42.86111; -91.15389
Country  United States
State  Iowa
County Humboldt
Established 1857
Area
 • Total 36.6 sq mi (95 km2)
 • Land 36.6 sq mi (95 km2)
 • Water 0.0 sq mi (0 km2)
Elevation 915 ft (279 m)
Population (2000)
 • Total 624
 • Density 17/sq mi (7/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)
ZIP codes 50558 (Livermore)
50560 (Lu Verne)
GNIS feature ID 0468060

Humboldt Township is one of twelve townships in Humboldt County, Iowa, USA.[1] As of the 2000 census, its population was 624. Despite its name, the township does not contain the City of Humboldt.

Geography[edit]

According to the United States Census Bureau, Humboldt Township covers an area of 36.6 square miles (95 km2); all of this is land.

Cities, towns, villages[edit]

Adjacent townships[edit]

Cemetery[edit]

The township contains Mount Calvary Cemetery.[1]

Political districts[edit]

References[edit]

  1. ^ a b "Humboldt township, Humboldt County, Iowa (IA)". U.S. Census Bureau. Breakdown. Retrieved January 21, 2010.

External links[edit]