Iridium(V) fluoride

From Wikipedia, the free encyclopedia
  (Redirected from Iridium pentafluoride)
Jump to navigation Jump to search
Iridium(V) fluoride
Unit cell of OsF5.png
Other names
Iridium pentafluoride
Molar mass 287.209 g/mol
Appearance yellow solid
Melting point 104.5 °C (220.1 °F; 377.6 K)
Related compounds
Other cations
Rhodium(V) fluoride, Osmium pentafluoride, Platinum(V) fluoride
Related compounds
Iridium(IV) fluoride, Iridium hexafluoride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
☑Y verify (what is ☑Y☒N ?)
Infobox references

Iridium(V) fluoride, IrF5, is a chemical compound of iridium and fluorine. A highly reactive yellow low melting solid, it has a tetrameric structure, Ir4F20, which contains octahedrally coordinated iridium atoms.[1] This structure is shared with RuF5 and OsF5. It can be prepared by the controlled decomposition of IrF6[1] or the reduction of IrF6 with silicon powder or H2 in anhydrous HF.[2][3]

See also[edit]


  1. ^ a b Egon Wiberg, Arnold Frederick Holleman (2001) Inorganic Chemistry, Elsevier ISBN 0-12-352651-5
  2. ^ Paine, Robert T.; Asprey, Larned B. (1975). "Reductive syntheses of transition metal fluoride compounds. Synthesis of rhenium, osmium, and iridium pentafluorides and tetrafluorides". Inorganic Chemistry. 14 (5): 1111–1113. doi:10.1021/ic50147a030.
  3. ^ Neil Bartlett and P. R. Rao (1965). "Iridium pentafluoride". Chem. Commun. (12): 252–253. doi:10.1039/C19650000252.