Iridium(V) fluoride

From Wikipedia, the free encyclopedia
  (Redirected from Iridium pentafluoride)
Jump to: navigation, search
Iridium(V) fluoride
Other names
Iridium pentafluoride
Molar mass 287.209 g/mol
Appearance yellow solid
Melting point 104.5 °C (220.1 °F; 377.6 K)
Related compounds
Other cations
Rhodium(V) fluoride, Osmium pentafluoride, Platinum(V) fluoride
Related compounds
Iridium(IV) fluoride, Iridium hexafluoride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
YesY verify (what is YesYN ?)
Infobox references

Iridium(V) fluoride, IrF5, is a chemical compound of iridium and fluorine, first described by Neil Bartlett in 1965.[1] A highly reactive yellow low melting solid, it has a tetrameric structure, Ir4F20, which contains octahedrally coordinated iridium atoms.[2] This structure is shared with RuF5 and OsF5. It can be prepared by the controlled decomposition of IrF6[2]or the reduction of IrF6 with silicon powder or H2 in anhydrous HF.[3]

See also[edit]


  1. ^ Neil Bartlett and P. R. Rao (1965). "Iridium pentafluoride". Chem. Commun. (12): 252–253. doi:10.1039/C19650000252. 
  2. ^ a b Egon Wiberg, Arnold Frederick Holleman (2001) Inorganic Chemistry, Elsevier ISBN 0-12-352651-5
  3. ^ Paine, Robert T.; Asprey, Larned B. (1975). "Reductive syntheses of transition metal fluoride compounds. Synthesis of rhenium, osmium, and iridium pentafluorides and tetrafluorides". Robert T. Paine, Larned B. Asprey. 14 (5): 1111–1113. doi:10.1021/ic50147a030.