Jefferson Township, Kosciusko County, Indiana

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Jefferson Township
Township
Map highlighting Jefferson Township, Kosciusko County, Indiana.svg
Coordinates: 41°23′27″N 85°56′03″W / 41.39083°N 85.93417°W / 41.39083; -85.93417Coordinates: 41°23′27″N 85°56′03″W / 41.39083°N 85.93417°W / 41.39083; -85.93417
Country United States
State Indiana
County Kosciusko
Government
 • Type Indiana township
Area
 • Total 31.52 sq mi (81.6 km2)
 • Land 31.47 sq mi (81.5 km2)
 • Water 0.06 sq mi (0.2 km2)
Elevation[1] 823 ft (251 m)
Population (2010)
 • Total 2,040
 • Density 64.8/sq mi (25.0/km2)
FIPS code 18-38052[2]
GNIS feature ID 453489

Jefferson Township is one of seventeen townships in Kosciusko County, Indiana. As of the 2010 census, its population was 2,040 and it contained 677 housing units.[3]

Jefferson Township was organized in 1838.[4]

Geography[edit]

According to the 2010 census, the township has a total area of 31.52 square miles (81.6 km2), of which 31.47 square miles (81.5 km2) (or 99.84%) is land and 0.06 square miles (0.16 km2) (or 0.19%) is water.[3]

References[edit]

  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  2. ^ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10. 
  4. ^ Biographical and Historical Record of Kosciusko County, Indiana. Lewis Publishing Company. 1887. p. 714. 

External links[edit]